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riadik2000 [5.3K]
3 years ago
10

What is the volume of the cone shown below?

Mathematics
1 answer:
STatiana [176]3 years ago
3 0
The formula to calculate the volume of a cone is:

V= \frac{1}{3}  \pi (radius)^2h

So, replace radius = 3in and h = 8 in.

The result is: [1/3] π (3in)^2 (8in) = [1/3]π(9)(8) in^3 = 24 π in^3

Answer: option b. 24 π in^3
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Hello please help i’ll give brainliest
Karolina [17]
A is the right answer,Brainly pls
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3 years ago
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<img src="https://tex.z-dn.net/?f=%20%5Clarge%5Cbegin%7Bbmatrix%7D%20%5Cbegin%7Barray%7D%20%7B%20l%20l%20%7D%20%7B%202%20%7D%20%
SVETLANKA909090 [29]

\huge \boxed{\mathbb{QUESTION} \downarrow}

\begin{bmatrix} \begin{array} { l l } { 2 } & { 3 } \\ { 5 } & { 4 } \end{array} \end{bmatrix} \begin{bmatrix} \begin{array} { l l l } { 2 } & { 0 } & { 3 } \\ { - 1 } & { 1 } & { 5 } \end{array} \end{bmatrix}

\large \boxed{\mathbb{ANSWER\: WITH\: EXPLANATION} \downarrow}

\begin{bmatrix} \begin{array} { l l } { 2 } & { 3 } \\ { 5 } & { 4 } \end{array} \end{bmatrix} \begin{bmatrix} \begin{array} { l l l } { 2 } & { 0 } & { 3 } \\ { - 1 } & { 1 } & { 5 } \end{array} \end{bmatrix}

In matrix multiplication, the number of columns in the 1st matrix is equal to the number of rows in the 2nd matrix.

\left(\begin{matrix}2&3\\5&4\end{matrix}\right)\left(\begin{matrix}2&0&3\\-1&1&5\end{matrix}\right)

Multiply each element of the 1st row of the 1st matrix by the corresponding element of the 1st column of the 2nd matrix. Then add these products to obtain the element in the 1st row, 1st column of the product matrix.

\left(\begin{matrix}2\times 2+3\left(-1\right)&&\\&&\end{matrix}\right)

The remaining elements of the product matrix are found in the same way.

\left(\begin{matrix}2\times 2+3\left(-1\right)&3&2\times 3+3\times 5\\5\times 2+4\left(-1\right)&4&5\times 3+4\times 5\end{matrix}\right)

Simplify each element by multiplying the individual terms.

\left(\begin{matrix}4-3&3&6+15\\10-4&4&15+20\end{matrix}\right)

Now, sum each element of the matrix.

\large\boxed{\boxed{\left(\begin{matrix}1&3&21\\6&4&35\end{matrix}\right) }}

7 0
2 years ago
I need help please :/
OleMash [197]

Part (a)

Plug in y = 0 and solve for x. Use the zero product property

y = x(x+3)(x-2)

0 = x(x+3)(x-2)

x(x+3)(x-2) = 0

x = 0 or x+3 = 0 or x-2 = 0 .... zero product property

x = 0 or x = -3 or x = 2

The three roots or zeros are x = 0 or x = -3 or x = 2

================================================

Part (b)

The roots of the graph are: x = -2, x = 1, x = 3. Each root is where the graph crosses or touches the horizontal x axis.

Note how x = 0 is found in part (a), but not found here. This is one example where the graphs don't match. Another would be x = -3 is in part (a), but not here.

So that's why the graph does <u>not</u> match with the function in part (a)

7 0
3 years ago
Which number is less than 3/20<br> A 2/11 <br> B1/6<br> C 13%<br> D 0.15
Juliette [100K]

Answer:

13% is less than 3/20.

Step-by-step explanation:

3/20 = .15

2/11 = .18(repeating)

1/6 = 1.6(repeating)7

13% = .13

and then .15

5 0
2 years ago
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-Dominant- [34]

Answer:

Step-by-step explanation:

they want to know the high and low quiz scores... that's all

6 0
2 years ago
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