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LuckyWell [14K]
3 years ago
9

Help me solve this I need to solve x again

Mathematics
1 answer:
sineoko [7]3 years ago
4 0
The answer should be 164, if the angles are vertical (across from another) they are the same so 164 times 1/2 is 82
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Please help math experts need your help 15 points !
Alinara [238K]

Answer:

12 = -3 - 3x

Step-by-step explanation:

Same concept as the last question I answered. First, let's derive a formula from the given model. So we have 3 negative x and 3 negative 1 which equal to 12 positive ones, this can be written as:

-3x - 3 = 12

which can be rewritten as

12 = -3 - 3x

7 0
3 years ago
Evaluate the expression -2​
DaniilM [7]

Answer:  2x for x=3: 2(3) = 6.

Step-by-step explanation:

6 0
3 years ago
The diagram below shows twelve 30-60-90 triangles placed in a circle so that the hypotenuse of each triangle coincides with the
julia-pushkina [17]

Answer:

m+n = 337

Step-by-step explanation:

Lets start from the first triangle, It is given to be as 30-60-90.

The hypotenous of first rectangle be 2x, then other sides are by default x and

\sqrt{3}(x) , using laws of trigonometry.

(sin(30) = 0.5  and cos(30) = \frac{\sqrt{3}}{2})

The perimeter of first triangle is ,

= 2x + x + \sqrt{3}(x) = x(3+\sqrt{3}) = \sqrt{3}x(1+\sqrt{3})

Now, for second triangle, the longer leg is 2x, and similarly again,

other 2 sides are \frac{2x}{\sqrt{3}}  and \frac{4x}{\sqrt{3}}.

Again the perimeter of triangle comes out as,

= \sqrt{3}(x)(1+\sqrt{3})(\frac{2}{\sqrt{3}})

Thus, the repeating pattern is identified. The consecutive perimeters differ by, multiplying by factor \frac{2}{\sqrt{3}}

Thus, we can say that perimeter of 4th triangle is,

= (\frac{2}{\sqrt{3}})^{3}(X), where X is the repeating constant.

And of 12th triangle is,

= (\frac{2}{\sqrt{3}})^{11}(X),

Evaluating the above ratio, we get,

= \frac{81}{256}

Thus, m =256 and n=81.

Thus, m+n = 256+81 = 337.

6 0
3 years ago
Write an equation for a circle with center at (–7, 10) and diameter = 6.
postnew [5]
Equation of a circle with center at (h,k) and radius of r is
(x-h)²+(y-k)²=r²

so
center (-7,10) and diameter 6
remember, diameter/2=radius=6/2=3

so
equation is (x-(-7))²+(y-10)²=3²
(x+7)²+(y-10)²=9
5 0
3 years ago
Add or subtract the linear expressions and simplify:
kherson [118]
0.1(71x+33)
the soultion is
6 0
3 years ago
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