Answer:
1) 36
b) 5
c) 3.0
Step-by-step explanation:
1) The recursive formula that defines the given sequence is

That means we keep adding 4 to the subsequent terms:
The sequence will be:
12,16,20,24,28,32,36,...
Therefore the seventh term is 36.
2) The sequence is recursively defined by;

This means, we have to keep subtracting 5 from the subsequent terms.
The sequence will be;
20,15,10,5,...
Therefore the fourth term is 5
3) The sequence is recursively defined by:
f(n+1)=f(n)+0.5
where f(1)=-1.5
This means that, the subsequent terms can be found by adding 0.5 to the previous terms.
The sequence will be:
-1.5,-1.0,-0.5,0,0.5,1,1.5,2.0,2.5,3.0,....
Therefore f(10)=3.0
Answer:-3
Step-by-step explanation:Could it be -3 if your learning about intercepts I need more information to help you further
The solution to the inequality |4x − 2| > 14 is x > 4 and x < -3
<h3>What is an
inequality?</h3>
An inequality is an expression that shows the non equal comparison of two or more numbers and variables.
Given the inequality:
|4x − 2| > 14
Hence:
4x - 2 > 14 or -(4x - 2) > 14
x > 4 or x < -3
The solution to the inequality |4x − 2| > 14 is x > 4 and x < -3
Find out more on inequality at: brainly.com/question/24372553
Answer:
the answer is 168
Step-by-step explanation:
you multiply with by length and you get 168.
9514 1404 393
Answer:
(i) x° = 70°, y° = 20°
(ii) ∠BAC ≈ 50.2°
(iii) 120
(iv) 300
Step-by-step explanation:
(i) Angle x° is congruent with the one marked 70°, as they are "alternate interior angles" with respect to the parallel north-south lines and transversal AB.
x = 70
The angle marked y° is the supplement to the one marked 160°.
y = 20
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(ii) The triangle interior angle at B is x° +y° = 70° +20° = 90°, so triangle ABC is a right triangle. With respect to angle BAC, side BA is adjacent, and side BC is opposite. Then ...
tan(∠BAC) = BC/BA = 120/100 = 1.2
∠BAC = arctan(1.2) ≈ 50.2°
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(iii) The bearing of C from A is the sum of the bearing of B from A and angle BAC.
bearing of C = 70° +50.2° = 120.2°
The three-digit bearing of C from A is 120.
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(iv) The bearing of A from C is 180 added to the bearing of C from A:
120 +180 = 300
The three-digit bearing of A from C is 300.