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Tju [1.3M]
2 years ago
10

Determine the sum of the Natural numbers up to 1000 which are not divisible by 5

Mathematics
1 answer:
Andrews [41]2 years ago
5 0

Sum the first 1000 natural numbers:

\displaystyle 1 + 2 + 3 + \cdots + 100 = \sum_{i=1}^{1000} i = \frac{1000 \cdot 1001}2 = 500,500

Since 1000/5 = 200, there are 200 multiples of 5 in the range 1-1000. Sum them up:

\displaystyle 5 + 10 + 15 + \cdots + 1000 = 5 (1 + 2 + 3 + \cdots + 200) = 5\sum_{i=1}^{200}i = 5\cdot\frac{200\cdot201}2 = 100,500

Then the sum we want is

\displaystyle 1 + 2 + 3 + 4 + 6 + 7 + 8 + 9 + 11 + \cdots + 999 = 500,500-100,500 = \boxed{400,000}

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Dmitriy789 [7]

Answer:

-  \frac{3}{13}  +  \frac{15i}{13}

Step-by-step explanation:

\frac{ \sqrt{ - 36} }{(2 - 3i) + (3 + 2i)}

Set up equation

Step 1: Simplify

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Step 2:Multiply by conjugate

\frac{6i}{5 - i}  \times  \frac{5 + i}{5 + i}

Step 3:Simplify

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The rhombus is shown in the diagram below

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3 years ago
M(-3,2) is the midpoint of AP. If A has coordinates (-1,5), what are the<br> coordinates of P?
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Answer:

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Step-by-step explanation:

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Answer:

Option (a)

Step-by-step explanation:

This question is incomplete without statements; find the statements as followed,

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