All categories

2 years ago

CAN SOMEONE HELP DO #1 PLEASE

Mathematics

1 answer:

love history [14]2 years ago

4 0

Answer:

B. $450

Step-by-step explanation:

The amount of commission is the commission rate (3%) times the amount of sales to which it is applied ($5000). Garrett's commission last week would be ...

0.03 × $5000 = $150

He is also paid $300 each week in addition to his commission, so his total pay last week was ...

pay = salary + commission

pay = $300 +150 = $450

You might be interested in

A waiter had fifty-seven customers. If twenty-three left, how many customers would the waiter still have?

Sav [38]

Answer:

Step-by-step explanation:

3 0

3 years ago

Read 2 more answers

How many solutions does the following equation have? 3(2+x)=3x+2=

fgiga [73]

6=2 no solution
first multiple the number in the left side
than subtract
than you will get 6=2 no solution

7 0

3 years ago

I need help how I resolve this

svlad2 [7]

To help you out I save your picture and explain the process. The only thing tht confuses me is problem #!6. But I hope I helped you out in the slightest bit

5 0

4 years ago

Can you help me with the last four? Thanks!!!

Lina20 [59]

When you have -(-2) it equals +2 and the same goes for any other number. When you have +(-2) it equals -2 and the same goes for any other number. Hope this helps!

4 0

3 years ago

Boxes of raisins are labeled as containing 22 ounces. Following are the weights, in the ounces, of a sample of 12 boxes. It is r

ZanzabumX [31]

Answer:

A 90% confidence interval for the mean weight is [21.78 ounces, 21.98 ounces].

Step-by-step explanation:

We are given the weights, in the ounces, of a sample of 12 boxes below;

Weights (X): 21.88, 21.76, 22.14, 21.63, 21.81, 22.12, 21.97, 21.57, 21.75, 21.96, 22.20, 21.80.

Firstly, the pivotal quantity for finding the confidence interval for the population mean is given by;

P.Q. = $\frac{\bar X-\mu}{\frac{s}{\sqrt{n} } }$ ~ $t_n_-_1$

where, $\bar X$ = sample mean weight = $\frac{\sum X}{n}$ = 21.88 ounces

s = sample standard deviation = $\sqrt{\frac{\sum (X-\bar X)^{2} }{n-1} }$ = 0.201 ounces

n = sample of boxes = 12

$\mu$ = population mean weight

Here for constructing a 90% confidence interval we have used a One-sample t-test statistics because we don't know about population standard deviation.

So, 90% confidence interval for the population mean, $\mu$ is ;

P(-1.796 < $t_1_1$ < 1.796) = 0.90 {As the critical value of t at 11 degrees of

freedom are -1.796 & 1.796 with P = 5%}

P(-1.796 < $\frac{\bar X-\mu}{\frac{s}{\sqrt{n} } }$ < 1.796) = 0.90

P( $-1.796 \times {\frac{s}{\sqrt{n} } }$ < ${\bar X-\mu}$ < $1.796 \times {\frac{s}{\sqrt{n} } }$ ) = 0.90

P( $\bar X-1.796 \times {\frac{s}{\sqrt{n} } }$ < $\mu$ < $\bar X+1.796 \times {\frac{s}{\sqrt{n} } }$ ) = 0.90

90% confidence interval for $\mu$ = [ $\bar X-1.796 \times {\frac{s}{\sqrt{n} } }$ , $\bar X+1.796 \times {\frac{s}{\sqrt{n} } }$ ]

= [ $21.88-1.796 \times {\frac{0.201}{\sqrt{12} } }$ , $21.88+1.796 \times {\frac{0.201}{\sqrt{12} } }$ ]

= [21.78, 21.98]

Therefore, a 90% confidence interval for the mean weight is [21.78 ounces, 21.98 ounces].

8 0

3 years ago