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ycow [4]
3 years ago
14

The amounts of paper waste generated in a region during two years were 41,300,000 tons and 50,500,000 tons. What was the total p

aper waste generated over these two years in the region, expressed in scientific notation?
Mathematics
2 answers:
zavuch27 [327]3 years ago
7 0
Just add 41,300,000 to 50,500,000. That is 91,300,000.00 tons. Scientific Notation just moves the decimal point to the beginning. So it would be 9.13*10^7
mezya [45]3 years ago
4 0
So first you need to add the two years together to get 91,800,000 from there you can start to turn it into scientific notations. First start out by putting an imaginary decimal point at the end so you have 91,800,000. From there you need to move the decimal next to the 9 so 7 spots to the left. This means that when you are converting back from SN you would go 7 spots to the right. Therefore when you write this in SN you will have 10 to the power of positive 7.Now that you have the number and the exponent you just put them together and you have 9.18 x 10^7 . I hope this helped and if you have any questions about how I got this answer feel free to message me.
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Researchers working the mean weight of a random sample of 800 carry-on bags to e the airline. Which of the following best descri
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Answer:

(E) The bias will decrease and the variance will decrease.

Step-by-step explanation:

Given that researchers working the mean weight of a random sample of 800 carry-on bags to e the airline.

We have to find out the effect of increasing the sample size on variance and bias.

We know as per central limit theorem, sample mean follows a normal distribution with mean = sample mean

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Thus std error the square root of variance is inversely proportional to the square root of sample size.

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8 0
3 years ago
If m&lt;ECD is six less than five times m&lt;BCE. and m&lt;BCD = 162°, find each measure.(Sorry bout using the wrong signs, but
tia_tia [17]

Answer:

m∠BCE = 28° and m∠ECD = 134°

Step-by-step explanation:

* Lets explain how to solve the problem

- The figure has three angles: ∠BCE , ∠ECD , and ∠BCD

- m∠ECD is six less than five times m∠BCE

- That means when we multiply measure of angle BCE by five and

 then subtract six from this product the answer will be the measure

 of angle ECD

∴ m∠ECD = 5 m∠BCE - 6 ⇒ (1)

∵ m∠BCD = m∠BCE + m∠ECD

∵ m∠BCD = 162°

∴ m∠BCE + m∠ECD = 162 ⇒ (2)

- Substitute equation (1) in equation (2) to replace angle ECD by

  angle BCE

∴ m∠BCE + (5 m∠BCE - 6) = 162

- Add the like terms

∴ 6 m∠BCE - 6 = 162

- Add 6 to both sides

∴ 6 m∠BCE = 168

- Divide both sides by 6

∴ m∠BCE = 28°

- Substitute the measure of angle BCE in equation (1) to find the

  measure of angle ECD

∵ m∠ECD = 5 m∠BCE - 6

∵ m∠BCE = 28°

∴ m∠ECD = 5(28) - 6 = 140 - 6 = 134°

* m∠BCE = 28° and m∠ECD = 134°

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