The length of B'C' in the rectangle A'B'C'D' = 9 units.
<u>Step-by-step explanation</u>:
step 1 :
Draw a rectangle with vertices ABCD in clockwise direction.
where, AB and DC are width of the rectangle ABCD.
AD and BC are length of the rectangle ABCD.
step 2 :
Now,
The length of the rectangle is AD = 5 units and
The width of the rectangle is AB = 3 units.
step 3 :
Draw another rectangle with vertices A'B'C'D' extended from vertices of the previous rectangle ABCD.
step 3 :
The length of the new rectangle is A'D' which is 4 units down from AD.
∴ The length of A'D' = length of AD + 4 units = 5+4 = 9 units
step 4 :
Since B'C' is also the length of the rectangle A'B'C'D', then the measure of B'C' is 9 units.
Answer:
B=1
Step-by-step explanation:
Any variable without explination is =1
Given that there were 30 bacteria present originally.
a=30
Also given that the number doubles every one hour.
After one hour the count =2×30=60
Since the count doubles every hour it forms a G.P. with r=2
a,ar,ar2........
The count at the end of 2nd hour=ar^2=30×2^2=120
The count at the end of 4th hour=ar^4=30×2^4=480
The count at the end of 8th hour=ar^8n=30×2^8=7680
etc.
The count at the end of n^th hour=ar^n=30×2^n
Also, the equation y=30*(2)^8/1 give the same result y= 7680
Answer:
58
Step-by-step explanation:
58.58 - 0.58 = 58