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pashok25 [27]
3 years ago
10

Simplify with positive exponents no radicals. SHOW ALL WORK!

Mathematics
1 answer:
Paraphin [41]3 years ago
3 0
For this case, what you should keep in mind are the following considerations:

 1) Rewrite the expressions correctly using the properties of the exponents: Addition, multiplication, division, subtraction and negative exponents.

 2) Simplify the expression as much as possible.

 Answer: 
 See attached image.

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12 out of 30 tickets sold were early admission what percentage of tickets were early admission tickets
bezimeni [28]

Answer:

40%

Step-by-step explanation:

12 divided by 30 will give you 0.4

7 0
3 years ago
Select the correct answer.
liraira [26]

Answer:

c and d

Step-by-step explanation:

4 0
3 years ago
Select all the statements that are true
masya89 [10]

Answer:

Options 2, 4 and 6 are True.

Step-by-step explanation:

Triangle MNO is dilated by a scale factor of \frac{3}{2} centered at M(0, 6).

Rule to be followed to dilate the vertices of the given triangle,

(x, y) → (kx, ky)

Here, k = scale factor

By this rule vertices of the new triangle M'N'O' will be,

M(0, 6) → M'(0, 6) [Coordinates of M' will remain same as M because center of dilation is point M]

N(-4, -4) → N'(-6, -6)

O(6, -2) → O'(9, -3)

Option 1

M'N' is shorter than MN

Distance between M and N = \sqrt{(0+4)^2+(6+4)^2}

                                              = 10.77

Distance between M' and N' = \sqrt{(0+6)^2+(6+6)^2}

                                                = 13.42

Therefore M'N' > MN

Therefore, Option A is False.

Option 2

ON is shorter than O'N'

True.

Option 3

OM is longer than O'M'

False

Option 4

ON is parallel to O'N'

Since OM and MN are dilated with the same scale factor, O'N' will be parallel to ON.

True.

Option 5

OM is parallel than O'M'

Since, O'M' is the dilated form of OM,

Therefore, all the points (O, M and M') will be in a straight line.

False

Option 6

M'N' coincide with MN

True.

Therefore, Options 2, 4 and 6 are True.

3 0
3 years ago
Suppose the heights of women at a college are approximately Normally distributed with a mean of 65 inches and a population stand
Zigmanuir [339]

Answer:

Step-by-step explanation:

Hello!

The variable of interest, X: height of women at a college, has an approximately normal distribution with mean μ= 65 inches and standard deviation σ= 1.5 inches.

You need to look for the value of height that marks the bottom 20% of the distribution, i.e. the height at the 20th percentile of the normal curve, symbolically:

P(X≤x₀)= 0.20

To know what value of height belongs to the 20% of the distribution, you have to work using the standard normal distribution and then reverse the standardization with the population mean and standard deviation to reach the value of X. So the first step is to look for the Z-value that accumulates 20% of the distribution:

P(Z≤z₀)=0.20

z₀= -0.842

z₀= (x₀-μ)/σ

z₀*σ= (x₀-μ)

x₀= (z₀*σ)+μ

x₀= (-0.842*1.5)+65

x₀= 63.737 inches

I hope it helps!

6 0
3 years ago
Read 2 more answers
Can someone please help me ASAP
charle [14.2K]

Answer:

(4,12)

(-1,-3)

Step-by-step explanation:

x^2 - y = 4

y = 3x

Use substitution.  Substitute 3x for y in the first equation

x^2 - (3x) = 4

x^2 -3x =4

Subtract 4 from each side

x^2 -3x -4 = 4-4

x^2 -3x-4 =0

Factor

(x-4) (x+1) =0

Using the zero product property

x-4 =0  x+1 =0

x=4   x=-1

Now to find y for each x solution

x=4

y =3x = 3(4) =12

(4,12)

x=-1

y =3x = 3(-1) =-3

(-1,-3)

4 0
3 years ago
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