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denis23 [38]
2 years ago
11

Find the equation of the given line. Round the numbers in the equation to the nearest tenth.

Mathematics
1 answer:
Nastasia [14]2 years ago
4 0

Answer:

its  A

Step-by-step explanation

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M is the midpoint of PQ, N is the midpoint of MQ, and L is the midpoint of MN. IfPQ = 64, find LN.
alisha [4.7K]
LN=8 because every time there is a midpoint you have to divide it in half. So 64,32,16,8
7 0
3 years ago
An island is 1 mi due north of its closest point along a straight shoreline. A visitor is staying at a cabin on the shore that i
Elanso [62]

Answer:

The visitor should run approximately 14.96 mile to minimize the time it takes to reach the island

Step-by-step explanation:

From the question, we have;

The distance of the island from the shoreline = 1 mile

The distance the person is staying from the point on the shoreline = 15 mile

The rate at which the visitor runs = 6 mph

The rate at which the visitor swims = 2.5 mph

Let 'x' represent the distance the person runs, we have;

The distance to swim = \sqrt{(15-x)^2+1^2}

The total time, 't', is given as follows;

t = \dfrac{x}{6} +\dfrac{\sqrt{(15-x)^2+1^2}}{2.5}

The minimum value of 't' is found by differentiating with an online tool, as follows;

\dfrac{dt}{dx}  = \dfrac{d\left(\dfrac{x}{6} +\dfrac{\sqrt{(15-x)^2+1^2}}{2.5}\right)}{dx} =  \dfrac{1}{6} -\dfrac{6 - 0.4\cdot x}{\sqrt{x^2-30\cdot x +226} }

At the maximum/minimum point, we have;

\dfrac{1}{6} -\dfrac{6 - 0.4\cdot x}{\sqrt{x^2-30\cdot x +226} } = 0

Simplifying, with a graphing calculator, we get;

-4.72·x² + 142·x - 1,070 = 0

From which we also get x ≈ 15.04 and x ≈ 0.64956

x ≈ 15.04 mile

Therefore, given that 15.04 mi is 0.04 mi after the point, the distance he should run = 15 mi - 0.04 mi ≈ 14.96 mi

t = \dfrac{14.96}{6} +\dfrac{\sqrt{(15-14.96)^2+1^2}}{2.5} \approx 2..89

Therefore, the distance to run, x ≈ 14.96 mile

6 0
3 years ago
Mandy built a pyramid for her project on Egypt with a volume of 483
emmainna [20.7K]

Answer

We have,

Volume of pyramid = 4834 in³

Base area of the pyramid = ?

Assuming height of the pyramid = 20 in

We know that

Volume of pyramid =\dfrac{hlw}{3}  

           4834=\dfrac{20\time lw}{3}  

           l w = 725.1 in²

Hence, area of the base of the pyramid is equal to 725.1 in².

4 0
3 years ago
2/3x + 1/6 = -3/4 x + 1
Marta_Voda [28]
Multiply all terms by 12/1 to get rid of fractions.
8x+2= -9x+12

Add 9x to both sides
17x+2=12

Subtract 2 from both sides
17x=10

Divide both sides by 17
x=10/17

Final answer: x=10/17
8 0
3 years ago
Ronaldo tossed a quarter and three dimes at the same time. The quarter landed heads up what is the probability that all the dime
givi [52]
I think 1/3 correct me someone if i'm wrong if i am srry

5 0
3 years ago
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