Answer:
- A'(4, -4)
- B'(0, -3)
- C'(2, -1)
- D'(3, -2)
Step-by-step explanation:
The coordinate transformation for a 270° clockwise rotation is the same as for a 90° counterclockwise rotation:
(x, y) ⇒ (-y, x)
The rotated points are ...
A(-4, -4) ⇒ A'(4, -4)
B(-3, 0) ⇒ B'(0, -3)
C(-1, -2) ⇒ C'(2, -1)
D(-2, -3) ⇒ D'(3, -2)
_____
<em>Additional comment</em>
To derive and/or remember these transformations, it might be useful to consider where a point came from when it ends up on the x- or y-axis.
A point must have come from the -y axis if rotating it 270° CW makes it end up on the +x-axis. A point must have come from the x-axis if rotating it 270° makes it end up on the +y axis. That is why we write ...
(x, y) ⇒ (-y, x) . . . . . . the new x came from -y; the new y came from x
When we have negative exponents, we can move the term with the exponent to the bottom of the fraction. This is also known as multiplying by the reciprocal (and changing the negative exponent to be positive!).
The reciprocal of z^-3 would be 1 / z^3.
Hope this helps!! :)
Answer:
the answer is 30
Step-by-step explanation:
Let the number be x
- 3 (x - 12) = - 54
-3x + 36 = -54
-3x = -54 - 36
-3x = -90
x = -90/-3
x = 30
Answer:
y = 2x + 7
Step-by-step explanation:
y = mx + b The point (-2,3) gives us an x value and a y value that we can use. We are also give the slope (m). All we need to do is figure out the b (y-intercept) value.
y = mx + b
3 = 2(-2) + b
3 = -4 + b Add for to both sides
7 = b We know have every thing that we need to write the equation. We have the slope (m) which is 2 and the b (y-intercept) that we just figured out is 7
y = 2x + 7
Answer:
m ∠RMK = 51°
Step-by-step explanation:
m ∠JMK = m ∠RMK + m ∠JMR
10x + 19 = 7x - 26 + 6x + 12
10x +19 = 13x -14
19 = 3x -14
33 = 3x
11 = x
m ∠RMK = 7(11) - 26 = 51°
m ∠JMR = 6 (11) + 12 = 78