<h3>
Answer: Choice B</h3>
Explanation:
Cosine is positive in quadrants I and IV, but quadrant IV isn't shaded in so we can rule out choice A.
Sine is positive in quadrants I and II. So far it looks like choice B could work. In fact, it's the answer because sin(pi/6) = 1/2 and sin(5pi/6) = 1/2. So if 0 ≤ sin(x) < 1/2, then we'd shade the region between theta = 0 and theta = pi/6; as well as the region from theta = 5pi/6 to theta = pi.
Choice C is ruled out because tangent is positive in quadrants I and III, but quadrant III isn't shaded.
Choice D is ruled out for similar reasoning as choice A. Recall that 
Answer:
14 - n
Step-by-step explanation:
Let the number be n.
14 - n
Answer:
2nd option
Step-by-step explanation:
The shaded area = outside area - inner area
= x² - (x - 6)² ← expand using FOIL
= x² - (x² - 12x + 36) ← distribute parenthesis by - 1
= x² - x² + 12x - 36 ← collect like terms
= 12x - 36