Question

Please Factor -5x²+13x+6

Answer 1

-(5x+3)(x-3)

Step-by-step explanation:

1.Factor out the negative sign.

-5x^2−13x−6

2.Split the second term in 5x^2−13x−6 into two terms.

−(5x^2+2x−15x−6)

3.Factor out common terms in the first two terms, then in the last two terms.

−(x(5x+2)−3(5x+2))

4.Factor out the common term 5x+2.

−(5x+2)(x−3)

Answer 2

Answer:

$(x-3)(-5x-2)$

or $-(x-3)(5x+2)$

Step-by-step explanation:

quadratic equation format: $a^2+b^2+c$

Therefore, for  $-5x^2+13x+6$,  a = -5, b = 13 and c = 6

Multiply the coefficient of $x^2$ ($a$) by the constant term ($c$)
$\implies -5 \times 6 = -30$

Find two numbers which have a product of -30 and a sum of $b$ (13)

Factors of 30:  1 and 30, 2 and 15, 3 and 10, 5 and 6

So -2 and 15 have a product of -30 and sum of 13.

Rewrite  $13x$  as  $15x-2x$  and substitute into the equation:

$\implies -5x^2+15x-2x+6$

Factorize the first two terms and the last two terms separately:

$\implies-5x(x-3)-2(x-3)$

The bracket created should always be the same.

The two brackets have now been found. The first bracket is the common factor of (x - 3). The second bracket is the factorized terms outside of each bracket (-5x - 2).

$\implies (x-3)(-5x-2)$

Additionally, we can write (-5x - 2) as -(5x + 2)

$\implies -(x-3)(5x+2)$