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Temka [501]
2 years ago
14

HELP!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!

Mathematics
1 answer:
Gre4nikov [31]2 years ago
7 0

Answer:

93° (to the nearest degree)

Step-by-step explanation:

sum of the interior angles of a triangle = 180°

Find angle C first, then subtract angle C and angle B from 180° to find angle A.

Use the sine rule \frac{sinA}{a}=\frac{sinB}{b}=\frac{sinC}{c} to find angle C:

Therefore,

              \frac{sinB}{b}=\frac{sinC}{c}

              \frac{sin38}{9}=\frac{sinC}{11}

         angle C = 48.80523914...°

Angle A = 180 - 38 - 48.80523914...°

              = 93.19476086..°

              = 93° (to the nearest degree)

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R/10+4=5 Can you help me balance the equation to simply? Thanks!
Dominik [7]

Subtract 4 from both sides

R/10 = 5 - 4

Simplify 5 - 4 to 1

R/10 = 1

Multiply both sides by 10

R = 1 × 10

Simplify 1 × 10 to 10

<u>R = 10</u>

3 0
3 years ago
NEED HELP ASAP!!! for geometry class
balandron [24]

Answer:

B) AAS

Step-by-step explanation:

B) AAS

5 0
3 years ago
Read 2 more answers
ME AYUDAN PORAVOR 1. Relaciona cada ecuación con su solución.
barxatty [35]

Answer:

a. 5 + x = -5 (Subtraction) 0.

b. -17 + x = 0 (Addition) 17.

c. 30 + x = 0 (Subtraction) -30.

d. x + (-27) = 0 (Addition) 27.

e. x + (-30) = 0 (Addition) 30.

Step-by-step explanation:

In this exercise, students are required to match each equation with its solution. (The corresponding operations must be presented at the end of this point

a. 5 + x = -5 (Subtraction) 0.

x = -5 - 5

x = 0

b. -17 + x = 0 (Addition) 17.

x = 0 + 17

x = 17

c. 30 + x = 0 (Subtraction) -30.

x = 0 - 30

x = -30

d. x + (-27) = 0 (Addition) 27.

x - 27 = 0

x = 0 + 27

x = 27

e. x + (-30) = 0 (Addition) 30.

x - 30 = 0

x = 0 + 30

x = 30

7 0
3 years ago
I need help with this question. I didn't choose answer D, but I accidentally did. If you could help me, that would be great.
Alex

Answer:

The correct answer would be B

Step-by-step explanation:

Plz Mark Brainlist

7 0
3 years ago
Math:
Dahasolnce [82]

Answer:

a) x_{1} = \frac{\pi}{3}\pm 2\pi \cdot i, \forall i \in \mathbb{N}_{O}, x_{2} = \frac{5\pi}{6}\pm 2\pi\cdot i, \forall i \in \mathbb{N}_{O}, b) x_{1} = \frac{\pi}{3}\pm 2\pi \cdot i, \forall i \in \mathbb{N}_{O}, x_{2} = \frac{5\pi}{3}\pm 2\pi\cdot i, \forall i \in \mathbb{N}_{O}

Step-by-step explanation:

a) The equation must be rearranged into a form with one fundamental trigonometric function first:

\sqrt{3}\cdot \csc x - 2 = 0

\sqrt{3} \cdot \left(\frac{1}{\sin x} \right) - 2 = 0

\sqrt{3} - 2\cdot \sin x = 0

\sin x = \frac{\sqrt{3}}{2}

x = \sin^{-1} \frac{\sqrt{3}}{2}

Value of x is contained in the following sets of solutions:

x_{1} = \frac{\pi}{3}\pm 2\pi \cdot i, \forall i \in \mathbb{N}_{O}

x_{2} = \frac{5\pi}{6}\pm 2\pi\cdot i, \forall i \in \mathbb{N}_{O}

b) The equation must be simplified first:

\cos x + 1 = - \cos x

2\cdot \cos x = -1

\cos x = -\frac{1}{2}

x = \cos^{-1} \left(-\frac{1}{2} \right)

Value of x is contained in the following sets of solutions:

x_{1} = \frac{\pi}{3}\pm 2\pi \cdot i, \forall i \in \mathbb{N}_{O}

x_{2} = \frac{5\pi}{3}\pm 2\pi\cdot i, \forall i \in \mathbb{N}_{O}

7 0
3 years ago
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