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3 years ago

Give the value of x that makes this equation true.

Mathematics

1 answer:

Anuta_ua [19.1K]3 years ago

5 0

The answer is C because 1 changes nothing

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∠EFG and ∠GFH are a linear pair, m∠EFG=3n+23, and m∠GFH=2n+32. What are m∠EFG and m∠GFH?

NARA [144]

the measures of the angles are:

m∠EFG = 98°
m∠GFH = 82°

<h3>How to find the measures of the angles?</h3>

Two angles are a linear pair if their measures add up to 180°.

Then we will have that:

∠EFG + ∠GFH = 180

Here we know that:

m∠EFG=3n+23

m∠GFH=2n+32

Replacing that we get:

3n + 23 + 2n + 32 = 180

5n + 55 = 180

5n = 180 - 55 = 125

n = 125/5 = 25

Then the measures of the angles are:

m∠EFG=3n+23 = 3*25 +23 = 98°

m∠GFH=2n+32 = 2*25 + 32 = 82°

If you want to learn more about angles:

brainly.com/question/17972372

#SPJ1

8 0

1 year ago

A manager at a local company asked his employees how many times they had given blood in the last year. The results of the survey

Lubov Fominskaja [6]

Answer:

$Var(X) = E(X^2) -[E(X)]^2 = 4.97 -(1.61)^2 =2.3779$

And the deviation would be:

$Sd(X) =\sqrt{2.3779}= 1.542 \approx 1.54$

Step-by-step explanation:

For this case we have the following distribution given:

X 0 1 2 3 4 5 6

P(X) 0.3 0.25 0.2 0.12 0.07 0.04 0.02

For this case we need to find first the expected value given by:

$E(X) = \sum_{i=1}^n X_i P(X_I)$

And replacing we got:

$E(X)= 0*0.3 +1*0.25 +2*0.2 +3*0.12 +4*0.07+ 5*0.04 +6*0.02=1.61$

Now we can find the second moment given by:

$E(X^2) =\sum_{i=1}^n X^2_i P(X_i)$

And replacing we got:

$E(X^2)= 0^2*0.3 +1^2*0.25 +2^2*0.2 +3^2*0.12 +4^2*0.07+ 5^2*0.04 +6^2*0.02=4.97$

And the variance would be given by:

$Var(X) = E(X^2) -[E(X)]^2 = 4.97 -(1.61)^2 =2.3779$

And the deviation would be:

$Sd(X) =\sqrt{2.3779}= 1.542 \approx 1.54$

8 0

3 years ago

Please help me quickly

Mumz [18]

Y is less than or equal to -1

7 0

3 years ago

Read 2 more answers

Find negative square root of 36. (4 points) Group of answer choices

AleksAgata [21]

Answer:

-5.65685424949

Step-by-step explanation:

7 0

2 years ago

1/5x-2/3y=30 when y=15

dolphi86 [110]

Answer:

Step-by-step explanation:

Step 1: Set y to 15 and solve

$\frac{1}{5}x - \frac{2}{3}*15=30$

$\frac{1}{5}x-10=30$

Add 10 to both sides

$\frac{1}{5}x-10+10=30+10$

$\frac{1}{5}x=40$

Multiply both sides by 5

$\frac{1}{5}x*\frac{5}{1}=40*\frac{5}{1}$

$x=200$

Answer: $x=200$

5 0

2 years ago