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3 years ago

Give the value of x that makes this equation true.

Mathematics

1 answer:

Anuta_ua [19.1K]3 years ago

5 0

The answer is C because 1 changes nothing

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Mr. Herkowitz owns a jewelry store. He marks up all merchandise 50 percent of

nasty-shy [4]

Answer:

$750

Step-by-step explanation:

5 0

3 years ago

Look at the picture. Solve for y

Mumz [18]

Answer:

y = 5

Step-by-step explanation:

Equation:

m<DGF = m<DGE + m<EGF

Given:

m<DGF = 12y - 5

m<DGE = 5y + 6

m<EGF = 24

Work:

m<DGF = m<DGE + m<EGF

12y - 5 = 5y + 6 + 24

12y - 5 = 5y + 30

12y - 5y = 30 + 5

7y = 35

y = 5

5 0

3 years ago

Let V be the event that a computer contains a virus, and let W be the event that a computer contains a worm. Suppose P(V) = 0.17

ArbitrLikvidat [17]

Answer: 0.82

Step-by-step explanation:

The probability of the computer not containing neither a virus nor a worm is expressed as P( $V^{C}$ ∩ $W^{C}$ ) , where P( $V^{C}$ ) is the probability that the event V doesn't happen and P( $W^{C}$ ) is the probability that the event W doesn't happen.

P( $V^{C}$ )= 1-P(V) = 1-0.17 = 0.83

P( $W^{C}$ )=1-P(W) = 1-0.05 = 0.95

Since $V^{C}$ and $W^{C}$ aren't mutually exclusive events, then:

P( $V^{C}$ ∪ $W^{C}$ ) = P( $V^{C}$ ) + P( $W^{C}$ ) - P( $V^{C}$ ∩ $W^{C}$ )

Isolating the probability that interests us:

P( $V^{C}$ ∩ $W^{C}$ )= P( $V^{C}$ ) + P( $W^{C}$ ) - P( $V^{C}$ ∪ $W^{C}$ )

Where P( $V^{C}$ ∪ $W^{C}$ ) = 1 - 0.04 = 0.96

Finally:

P( $V^{C}$ ∩ $W^{C}$ ) = 0.83 + 0.95 - 0.96 = 0.82

5 0

3 years ago

Plz answer the question below

solmaris [256]

X equal to 6 plus 1 by 3 which is 19 by 3 is the answer which is also a improper fraction

7 0

3 years ago

Read 2 more answers

A PHN is studying the rate of H1N1 in the community. If there are five cases of H1N1 in the community of 1,000 people, what is t

BigorU [14]

Answer:

0.5%

Step-by-step explanation:

The prevalence rate shows the proportion of people that have a disease in a population and to be able to calculate it, you have to divide the number of people that have a disease by the population:

Prevalence rate=(5/1,000)*100

Prevalence rate=0.005*100

Prevalence rate=0.5%

According to this, the answer is that if there are five cases of H1N1 in the community of 1,000 people, the prevalence rate is 0.5%.

8 0

3 years ago