Question

Pllllzzzzz hellllpppp!!! What is an equation of the line that passes through the point (2,2) and is parallel to the line x-2y=4

Answer 1

Answer:

x - 2y = - 2

Step-by-step explanation:

The equation of a line in slope- intercept form is

y = mx + c ( m is the slope and c the y- intercept )

Given

x - 2y = 4 ( subtract x from both sides )

- 2y = - x + 4 ( divide all terms by - 2 )

y = $\frac{1}{2}$ x - 2 ← in slope- intercept form

with slope m = $\frac{1}{2}$

Parallel lines have equal slopes, thus

y = $\frac{1}{2}$ x + c ← is the partial equation

To find c substitute (2, 2) into the partial equation

2 = 1 + c ⇒ c = 2 - 1 = 1

y = $\frac{1}{2}$ x + 1 ← equation in slope- intercept form

Multiply through by 2

2y = x + 2 ( subtract 2y from both sides )

0 = x - 2y + 2 ( subtract 2 from both sides )

- 2 = x - 2y, that is

x - 2y = - 2 ← equation in standard form

Answer 2

Answer:

-2y = 4 - x

2y = x - 4

y = 1/2x - 2

1/2 is the slope of both lines.

y = mx + b

Substitute the given point and the common slope

2 = 1/2 x 2 + b

2 = 1 + b

b = 1

y = 1/2x + 1

The equation of the line that passes through the point

(2, 2) and is parallel to the line x - 2y = 4 is y = 1/2x + 1 or 2y = x + 2.

hope this helps u

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