A) The total number is the sum of all the frequencies
2+5+8+12+11+6=44
Answer: 44
B) The width is (upper limit - lower limit) / 2
(35-21) / 2 = 7
(50-36) / 2 = 7
(65-51) / 2 = 7
(80-66) / 2 = 7
(95-81) / 2 = 7
(110-96) / 2 = 7
Answer: the width is 7
C) The midpoint is the lower limit + the width
36+7=43
Answer: the midpoint is 43
D)The modal is the class with more frequency
In this case 66-80 with 12
Answer: class 66-80
E) We use the width formula
lower limit = 111
width = 7
upper = (width * 2) - lower
upper = (7 * 2) + 111
upper = 125
Answer: class 111-125
Answer:
the answer is tbh .
Step-by-step explanation:
Answer:
−2(3x+12y−5−17x−16y+4)
=(−2)(3x+12y+−5+−17x+−16y+4)
=(−2)(3x)+(−2)(12y)+(−2)(−5)+(−2)(−17x)+(−2)(−16y)+(−2)(4)
=−6x−24y+10+34x+32y−8
=28x+8y+2
<h2>
(~ ̄▽ ̄)~ -Have a wonderful day-</h2>
Answer:
Step-by-step explanation:
Given that:
F(x, y, z) = 5xi - 5yj - 3zk
The objective is to evaluate the
and C is given by the vector function r(t) = (sin t, cost, t) where 0 ≤ t ≤ π
∴
By dividing 2 with 10 and integrating ; we have:
Answer:
Step-by-step explanation:
1) y = 2x ----------(I)
x + y = 6 -----------(II)
Plug in y =2x in equation (II)
x + 2x = 6 {Add like terms}
3x = 6
x = 6/3
x = 2
Plugin x = 2 in (I)
y = 2*2
y = 4
<u>Check: </u>
LHS = x +y
= 2 + 4
= 6 = RHS
2)5x + 10y = 3 ------------(I)
x = (-1/2) y ------------(II)
Substitute x = (-1/2)y in (I)
Substitute y = (2/5) in equation (II)
<u>Check:</u>
Substitute x and y value in equation (I)
3) y - x = 3x + 2
y = 3x + 2 + x
y = 4x + 2 ---------------(I)
2x + 2y = 14 - y
2x + 2y +y = 14
2x + 3y = 14 ------------------(II)
Substitute y = 4x + 2 in equation (II)
2x + 3(4x +2) = 14
2x + 3*4x + 3*2 = 14
2x + 12x + 6 = 14
14x + 6 = 14
14x = 14 - 6
14x = 8
x = 8/14
x = 4/7
Substitute 'x' value in (I)
<u>Check:</u>
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