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baherus [9]
2 years ago
11

David drove 870 miles in 12 hours. At what rate did David drive per hour?

Mathematics
2 answers:
Montano1993 [528]2 years ago
8 0

Answer:

72.5m/hr

Step-by-step explanation:

Divide 870 by 12 to represent how many miles David drove in 1 hour.

870 \div 12=72.5

David drove 72.5 miles per hour.

Roman55 [17]2 years ago
7 0

Answer:

the answer is 72.5

Step-by-step explanation:

so all you have to do is divide 870 by 12 and you get 72.5

hope this helps

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Assume that T is a linear transformation. Find the standard matrix of T. T: R^3 right arrow R^2 , T(e 1) =(1,2), and T(e2 ) =( -
irina [24]

Answer:

A = \left[\begin{array}{ccc}1&-4&2\\2&6&-6\end{array}\right]

Step-by-step explanation:

Given

T:R^3->R^2

T(e_1) = (1,2)

T(e_2) = (-4,6)

T(e_3) = (2,-6)

Required

Find the standard matrix

The standard matrix (A) is given by

Ax = T(x)

Where

T(x) = [T(e_1)\ T(e_2)\ T(e_3)]\left[\begin{array}{c}x_1&x_2&x_3\\-&&x_n\end{array}\right]

Ax = T(x) becomes

Ax = [T(e_1)\ T(e_2)\ T(e_3)]\left[\begin{array}{c}x_1&x_2&x_3\\-&&x_n\end{array}\right]

The x on both sides cancel out; and, we're left with:

A = [T(e_1)\ T(e_2)\ T(e_3)]

Recall that:

T(e_1) = (1,2)

T(e_2) = (-4,6)

T(e_3) = (2,-6)

In matrix:

(a,b) is represented as: \left[\begin{array}{c}a\\b\end{array}\right]

So:

T(e_1) = (1,2) = \left[\begin{array}{c}1\\2\end{array}\right]

T(e_2) = (-4,6)=\left[\begin{array}{c}-4\\6\end{array}\right]

T(e_3) = (2,-6)=\left[\begin{array}{c}2\\-6\end{array}\right]

Substitute the above expressions in A = [T(e_1)\ T(e_2)\ T(e_3)]

A = \left[\begin{array}{ccc}1&-4&2\\2&6&-6\end{array}\right]

Hence, the standard of the matrix A is:

A = \left[\begin{array}{ccc}1&-4&2\\2&6&-6\end{array}\right]

6 0
3 years ago
sing traditional methods, it takes 108108 hours to receive a basic driving license. A new license training method using Computer
solniwko [45]

Answer:

z_{stat} = -1.50            

Step-by-step explanation:

We are given the following in the question:

Population mean, μ = 108

Sample mean, \bar{x} = 107

Sample size, n = 110

Alpha, α = 0.02

Population standard deviation, σ = 7

Formula:

z_{stat} = \displaystyle\frac{\bar{x} - \mu}{\frac{\sigma}{\sqrt{n}} }

Putting all the values, we have

z_{stat} = \displaystyle\frac{107 - 108}{\frac{7}{\sqrt{110}} } = -1.50

The test statistic is -1.50

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