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konstantin123 [22]
4 years ago
5

An instructor has given a short quiz consisting of two parts. for a randomly selected student, let x = the number of points earn

ed on the first part and y = the number of points earned on the second part. suppose that the joint pmf of x and y is given in the accompanying table. y p(x, y) 0 5 10 15 x 0 0.02 0.06 0.02 0.10 5 0.04 0.13 0.20 0.10 10 0.01 0.15 0.16 0.01 (a) if the score recorded in the grade book is the total number of points earned on the two parts, what is the expected recorded score e(x + y)? (enter your answer to one decimal place.) (b) if the maximum of the two scores is recorded, what is the expected recorded score? (enter your answer to two decimal places.)
Mathematics
1 answer:
Diano4ka-milaya [45]4 years ago
8 0
<span>To find the expected recorded score, we need to find the sum of (x + y) times P(x +y), which gives us 14.4. The expected recorded score goes through the same process, but we only use the maximum scores and this gives us 9.75</span>
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Four cards are dealt from a standard fifty-two-card poker deck. What is the probability that all four are aces given that at lea
elena-s [515]

Answer:

The probability is 0.0052

Step-by-step explanation:

Let's call A the event that the four cards are aces, B the event that at least three are aces. So, the probability P(A/B) that all four are aces given that at least three are aces is calculated as:

P(A/B) =  P(A∩B)/P(B)

The probability P(B) that at least three are aces is the sum of the following probabilities:

  • The four card are aces: This is one hand from the 270,725 differents sets of four cards, so the probability is 1/270,725
  • There are exactly 3 aces: we need to calculated how many hands have exactly 3 aces, so we are going to calculate de number of combinations or ways in which we can select k elements from a group of n elements. This can be calculated as:

nCk=\frac{n!}{k!(n-k)!}

So, the number of ways to select exactly 3 aces is:

4C3*48C1=\frac{4!}{3!(4-3)!}*\frac{48!}{1!(48-1)!}=192

Because we are going to select 3 aces from the 4 in the poker deck and we are going to select 1 card from the 48 that aren't aces. So the probability in this case is 192/270,725

Then, the probability P(B) that at least three are aces is:

P(B)=\frac{1}{270,725} +\frac{192}{270,725} =\frac{193}{270,725}

On the other hand the probability P(A∩B) that the four cards are aces and at least three are aces is equal to the probability that the four card are aces, so:

P(A∩B) = 1/270,725

Finally, the probability P(A/B) that all four are aces given that at least three are aces is:

P=\frac{1/270,725}{193/270,725} =\frac{1}{193}=0.0052

5 0
4 years ago
Amelia uses 66 patches of fabric per square foot to make a blanket. How many patches of fabric will she need to make a blanket t
poizon [28]
The answer is 10920. 720720/66=10920
3 0
4 years ago
1 US Dollar =13.05 pesos 1meter =1.094 yars
Evgesh-ka [11]

Answer:

$18.01

Step-by-step explanation:

Convert from pesos to US dollars

6429/13.05 = $492.64

Convert from meters to yards

1.904* 25= 27.35

Divide to find the cost of one yard of fabric

492.64/27.35 = $18.01

4 0
3 years ago
John left a $2 tip for the server when stopped at a diner. If this was 20% of his order total, how much was his order?
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The answer is 10 dollars
4 0
3 years ago
Read 2 more answers
What the value of r that makes the value true? r+(-0.14)=0.47
siniylev [52]

r+(-0.14)=0.47\\\\r-0.14=0.47\qquad|\text{add 0.14 to both sides}\\\\r-0.14+0.14=0.47+0.14\\\\r=0.61

4 0
3 years ago
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