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nignag [31]
3 years ago
11

One solution to the problem below is 10. what is the other solution? problem:b^2-100=0

Mathematics
2 answers:
LenaWriter [7]3 years ago
8 0

Answer:

b^2=100

b=10 or b=-10

Step-by-step explanation:

AfilCa [17]3 years ago
5 0

Answer:

b₂ = - 10

Step-by-step explanation:

b² - 100 = 0

b² - 10² = 0

(b - 10)(b + 10) = 0

b₁ = 10

b₂ = - 10

a² - b² = (a - b)(a + b)

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3 years ago
PLEASE HELP ILL MARK BRAINLIEST !!!
Alexus [3.1K]

Answer:

a) the common difference is 20

b) x_8=115 , x_{12}=195

c) the common difference is -13

d) a_{12}=52, a_{15}=13

Step-by-step explanation:

a) what is the common difference of the sequence xn

Looking at the table, we get x_3=16, x_4=36 and x_5= 56

Deterring the common difference by subtracting x_4 from x_3 we get

36-16 =20

So, the common difference is 20

b) what is x_8? what is x_12

The formula used is: x_n=x_1+(n-1)d

We know common difference d= 20, we need to find x_1

Using x_3=16 we can find x_1

x_n=x_1+(n-1)d\\x_3=x_1+(3-1)d\\15=x_1+2(20)\\15=x_1+40\\x_1=15-40\\x_1=-25

So, We have x_1 = -25

Now finding x_8

x_n=x_1+(n-1)d\\x_8=x_1+(8-1)d\\x_8=-25+7(20)\\x_8=-25+140\\x_8=115

So, \mathbf{x_8=115}

Now finding x_{12}

x_n=x_1+(n-1)d\\x_{12}=x_1+(12-1)d\\x_{12}=-25+11(20)\\x_{12}=-25+220\\x_{12}=195

So, \mathbf{x_{12}=195}

c) what is the common difference of the sequence a_m

Looking at the table, we get a_7=104, a_8=91 and a_9= 78

Deterring the common difference by subtracting a_7 from a_8 we get

91-104 =-13

So, the common difference is -13

d) what is a_12? what is a_15?

The formula used is: a_n=a_1+(n-1)d

We know common difference d= -13, we need to find a_1

Using a_7=104 we can find x_1

a_n=a_1+(n-1)d\\a_7=a_1+(7-1)d\\104=a_1+7(-13)\\104=a_1-91\\a_1=104+91\\a_1=195

So, We have a_1 = 195

Now finding a_{12} , put n=12

a_n=a_1+(n-1)d\\a_{12}=a_1+(12-1)d\\a_{12}=195+11(-13)\\a_{12}=195-143\\a_{12}=52

So, \mathbf{a_{12}=52}

Now finding a_{15} , put n=15

a_n=a_1+(n-1)d\\a_{15}=a_1+(15-1)d\\a_{15}=195+14(-13)\\a_{15}=195-182\\a_{15}=13

So, \mathbf{a_{15}=13}

5 0
3 years ago
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1. would have to be team E because add up all the numbers 1058/8 (which is how many numbers that is there) 132.25.

2. (More of an explanation if you still don't understand)

52+52+53+54+55+55=321/6=53.5

52+53+54+55+57+57=328/6=54.66 repeated rounded to 54.7 so your answer is 1.2

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3 years ago
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Answer:

Mary was paid $638

Step-by-step explanation:

Mary was paid 360 $ for working alone because

$40 * 9 = $360

Mary was paid $278

5 % * $5560 = $278

360 + 278 = 638 $

5 0
2 years ago
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