Answer:
900
Step-by-step explanation:
We assume that your 4-digit number must be in the range 1000 to 9999. Clearly, any number ending in zero will meet your requirement:
1000/100 = 10
3890/389 = 10
However, the requirement cannot be met when the 1s digit is other than zero.
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For some 3-digit number N and some 1s digit x, the 4-digit number will be
4-digit number: 10N+x
Dividing this by N will give ...
(10N+x)/N = 10 remainder x
N will only be a factor of 10N+x when x=0.
So, there are 900 4-digit numbers that meet your requirement. They range from 1000 to 9990.
Answer:
5
Step-by-step explanation:
x = -6
-4x + y = 29
substitute x = -6 in -4x + y =29
-4(-6) + y = 29
24 + y = 29
subtract 24 from both sides
24 - 24 + y = 29 - 24
y = 5
The equation is y=2x-2
To find the x-value you take any two pairs of value such as (-2,-3) and (0,-2) and you just use y1-y2/x1-x2. And for y-value you just see when x is zero
Suppose that some value, c, is a point of a local minimum point.
The theorem states that if a function f is differentiable at a point c of local extremum, then f'(c) = 0.
This implies that the function f is continuous over the given interval. So there must be some value h such that f(c + h) - f(c) >= 0, where h is some infinitesimally small quantity.
As h approaches 0 from the negative side, then:

As h approaches 0 from the positive side, then:

Thus, f'(c) = 0
Answer:
d = -2
Step-by-step explanation:
d( 3 ) = ( -6 / d )d
3d = -6
(3d)/3 = (-6)/3
d = -2