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zheka24 [161]
2 years ago
6

Please help I need this please help please just me help

Mathematics
1 answer:
Nikitich [7]2 years ago
3 0

Answer:

It would take 4 minutes.

Step-by-step explanation:

Step 1: divide 63 by 3 to get how many hotdogs the champion can eat in a minute which equals 21

Step 2: Divide 84 by 21 to get 4 minutes

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The length of the radius of the larger cone would be 9 ft.
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Whats the ratio of 0.6 to 12 to the lowest term
Westkost [7]
You would divide the numbers as much as possible until you get to a point where they will not divide any more. So,
<u>0.6</u>= (Divide by 2) =<u>0.3</u>= (divide by 3) =<u>0.1</u>    <u>
</u>12                          6                           2
<u>
</u>After that, you cannot divide any more, so the final answer is 0.1/2 or 0.1:2 or 
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3 years ago
Write to explain how to break apart addends to find the sum of 324+231
Alenkinab [10]
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Read 2 more answers
which of these story problems describes the sum 19 + (-12)? check all that apply. show your work to justify your answer.
DanielleElmas [232]

which of these story problems describes the sum 19 + (-12)? check all that apply. show your work to justify your answer.

1

2. is the right answer

3

3 0
3 years ago
15 pts. Prove that the function f from R to (0, oo) is bijective if - f(x)=x2 if r- Hint: each piece of the function helps to "c
solniwko [45]

Answer with explanation:

Given the function f from R  to (0,\infty)

f: R\rightarrow(0,\infty)

-f(x)=x^2

To prove that  the function is objective from R to  (0,\infty)

Proof:

f:(0,\infty )\rightarrow(0,\infty)

When we prove the function is bijective then we proves that function is one-one and onto.

First we prove that function is one-one

Let f(x_1)=f(x_2)

(x_1)^2=(x_2)^2

Cancel power on both side then we get

x_1=x_2

Hence, the function is one-one on domain [tex[(0,\infty)[/tex].

Now , we prove that function is onto function.

Let - f(x)=y

Then we get y=x^2

x=\sqrt y

The value of y is taken from (0,\infty)

Therefore, we can find pre image  for every value of y.

Hence, the function is onto function on domain (0,\infty)

Therefore, the given f:R\rightarrow(0.\infty) is bijective function on (0,\infty) not on  whole domain  R .

Hence, proved.

3 0
3 years ago
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