A
a) y+6x=5 if x= -1 then y+6(-1)=5 then y = 11
b) same thing if x = 3 then y+6(3)=5 y+18=5 subtract both sides by -18 and leave y on left then add 5+(-18)= 13 then y=13
B same as above
question (a) asks you to solve for y because x is -2
(b) asks you to solve for x because y is known
3x+2y=-6 if y = 3 you write 3x+2(3)=-6 3x+6=-6 move the +6 over to right side by subtracting 6 from both side 3x=-6 + -6 so 3x=-12 to get rid of the 3 and only leave the x you want to divide both side by 3 then x= -12/3 then the answer would be x=-4
The ordered pair (6,9) follows the pattern in the graph.
For every 2 on the x coordinate, there is 3 for the y coordinate. (2,3) (4,6) (6,9) (8,12) and so on.
The answer to this problem is b.
The current Brainliest answer seems to be answering the question "Every integer is a multiple of which number?" rather than the question presented here.
We say that one number is a <em>multiple </em>of a second number if we can get to the first one by <em>counting by the second</em>. For example, 18 is a multiple of 6 because we can reach it by counting by 6's (6, 12, <em>18</em>). Note that, for any number we want to count by, we can always start our count at 0.
By 2's: 0, 2, 4, 6, 8
By 6's: 0, 6, 12, 18
By 7's: 0, 7, 14, 21
Because we can always "reach" 0 regardless of the integer we're counting by, we can say that <em>0 is a multiple of every integer</em>.
More formally, we say that some number n is a multiple of an integer x if we can find another integer y so that x · y = n. By this definition, 18 would be a multiple of 6 because 6 · 3 = 18, and 3 is an integer. We can use the property that the product of any number and 0 is 0 to say that x · 0 = 0, where x can be any integer we want. Since 0 is also an integer, this means that, by definition, 0 is a multiple of every integer.
