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2 years ago

Calculate the value of 0. Write your equation.

Mathematics

2 answers:

Crazy boy [7]2 years ago

3 0

Answer:

θ = 67.4°

Step-by-step explanation:

using the <u>SOHCAHTOA </u>method,

Here opposite is 12 cm, hypotenuse is 13 cm, adjacent is 5 cm.

Using the formula:

$sin(\beta ) = \frac{oppsoite }{hypotenuse}$

$sin(\beta ) = \frac{12}{13}$

$\beta = sin^{-1}(\frac{12}{13} )$

β = 67.4°

sweet [91]2 years ago

3 0

Right angle triangle so apply trigonometric identies.

$\\ \tt\hookrightarrow cos\theta=\dfrac{5}{13}$

$\\ \tt\hookrightarrow cos\theta=0.37$

$\\ \tt\hookrightarrow \theta=cos^{-1}(0.37)$

$\\ \tt\hookrightarrow \theta=68.3$

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Given f(x) = x^2 – 3x – 2, what is f(5)?

miskamm [114]

Answer:

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Step-by-step explanation:

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2 years ago

Read 2 more answers

getting home from trick or treat celia and emma counted their candies. half of celias candies is equal to 2/3 of emmas candies.

blagie [28]

Candies with celias and emmas is 60 and 45 respectively.

<u>Solution:</u>

Given, Getting home from trick or treat celia and emma counted their candies. Half of celias candies is equal to 2/3 of emmas candies.

They had a total of 105 candies altogether.

We have to find how many candies did each of them have.

Let the number of candies with celias be n, then number of candies with emma will be 105 – n.

Now according to given condition.

$\begin{array}{l}{\frac{1}{2} \times \text { celias candies count }=\frac{2}{3} \times \text { emmas candies count }} \\\\ {\rightarrow \frac{1}{2} \times n=\frac{2}{3} \times(105-n)} \\\\ {\rightarrow 3 \times n=2 \times 2 \times(105-n)} \\\\ {\rightarrow 3 \times n=2 \times 2 \times(105-n)} \\\\ {\rightarrow 3 n=4(105-n)} \\\\ {\quad \rightarrow 3 n=420-4 n} \\\\ {\rightarrow 3 n=420-4 n} \\\\ {\rightarrow 3 n+4 n=420} \\\\ {\rightarrow 7 n=7 \times 60} \\\\ {\rightarrow n=60}\end{array}$

Hence, candies with celias and emmas is 60 and 45 respectively.

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3 years ago

I’m so stupid I don’t know

adell [148]

Answer:

I am stupid too, so forgive me if I am wrong.ಥ_ಥ

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Maurinko [17]

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