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Arturiano [62]
2 years ago
11

PLEASE HELP BEFORE MIDNIGHT 2/14/22

Mathematics
1 answer:
vivado [14]2 years ago
7 0

Answer:

alright this is last question I'm able to answer because I got to finish my essay I'll be back tomorrow to help more if you need it I'm pretty sure this is b

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Which two expressions is equivalent to 8(5+x)
Natali [406]

Answer: 8(x+5) 8x + 40

40 + 8x

Step-by-step explanation:

Distribute the 8 by multiplying by each value inside the parentheses.

Commutative property in addition and multiplication allows the terms to be in reversed order.

4 0
3 years ago
Graph the image of Kite BCDE after a translation 5 units down.​
NeTakaya

Answer:

See attachment for the translated kite

<em></em>

Step-by-step explanation:

Given

The attached image of BCDE

Required

Translate 5 units down

From the attachment;

B = (-7,0)

C = (0,5)

D =(-7,10)

E = (-10,5)

The rule to translate 5 units down is:

(x,y) \to (x,y-5)

So:

B' = (-7,-5)

C' = (0,0)

D' = (-7,5)

E' = (-10,0)

<em>See attachment for the translated kite</em>

3 0
3 years ago
What is the greatest common factor of 16, 20, and 6?
KatRina [158]

Answer:

2

Step-by-step explanation:

5 0
3 years ago
Read 2 more answers
How old is the earth​
lyudmila [28]

Answer:

4.543 billion years

Step-by-step explanation:

3 0
3 years ago
Three kids, Alberto, Bernadette, and Carlos, decide to share 11 cookies. They wonder how many ways they could split the cookies
Luda [366]

Using the arrangements formula, it is found that they find 46200 ways.

<h3>What is the arrangements formula?</h3>

The number of arrangements of n elements is given by:

A_n = n!

If they repeat in n_1, n_2, \cdots, n_n ways, the number of arrangements is given by:

A_n^{n_1, n_2, \cdots, n_n} = \frac{n!}{n_1!n_2!\cdots n_n}

In this problem, 11 elements are arranged with repetitions of 4, 3 and 3, hence:

T = \frac{11!}{4!3!3!} = 46200

They find 46200 ways.

More can be learned about arrangements at brainly.com/question/2259733

5 0
2 years ago
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