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Alexandra [31]
3 years ago
11

J is the midpoint of HK¯¯¯¯¯¯¯ . What are HJ, JK, and HK?

Mathematics
1 answer:
lana [24]3 years ago
4 0
Since J is the midpoint of HK, that means HK is split into two sections HJ and JK that are the same length.

1) You are told that the m<span>easure of segment HJ = 9x-2 and that of segment JK = 4x+13. Since you also know they are equal lengths, you can set these equations equal to each other to find the value of x!
HJ = JK
</span>9x-2 = 4x+13
5x = 15
x = 3

2) Now you know x = 3. Plug that into your given equations for HJ and JK to find the length of each segment (or a shortcut would be to find one of them, and then you also know the other is the same length. I'm doing both, just to make sure I don't make a silly mistake!):
HJ = <span>9x-2 
</span>HJ = 9(3) - 2
HJ = 27 - 2
HJ = 25

JK = 4x + 13
JK = 4(3) + 13
JK = 12 + 13
JK = 25

3) Finally, the length of HK is just the length of HJ + JK, or HK = 25 + 25 = 50.

-----

Answer: HJ = 25, JK = 25, HK = 50
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Plz help me how would you solve 4x + 2y = 18, 3x - 5y =20 by elemination
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Answer: x = 5, y = -1

<u>Step-by-step explanation:</u>

Equation 1: 4x + 2y = 18

Equation 2: 3x - 5y = 20

In order to eliminate one of the variables , find the LCM of either x or y.

<em>I chose to eliminate y.</em>  The LCM of 2 & 5 is 10.

Multiply the entire equation so the coefficient of the variable equals the LCM.

Then add the equations and solve for the remaining variable.

5(4x + 2y = 18)       -->        20x + 10y = 90

2(3x - 5y = 20)      -->        <u>   6x  - 10y</u> = <u>40 </u>

                                           26x          = 130  

                                         <u> ÷26         </u>    <u>÷26 </u>

                                                x         =  5

Next, input x = 5 into either of the equations to solve for y.

Equation 1: 4x + 2y = 18

                 4(5) + 2y = 18

                  20  + 2y = 18

                <u> -20          </u>  <u>-20 </u>

                           2y = -2

                         <u> ÷2  </u>  <u> ÷2 </u>

                             y = -1

8 0
3 years ago
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