Answer:
It would be 2
Step-by-step explanation:
A (0, 3) *2= A' (0,6)
B (2,3)*2= B' (4,6)
C (3,2)*2=C' (6,4)
D (1,2)*2=D' (2,4)
Y = -5x - 4
switch x and y and solve for y
x = -5y - 4
x+4 = -5y
(x+4)/ -5 = y^-1 ( the inverse)
1/3
3/9
4/12
are equivalent to 2/6
X = 4 ; x = 3 + i ; x = 3 - i
(If you get a zero that is adding or subtracting, you always need to write it twice but change the sign do they cancel out)
f(x) = (x-4)(x-3-i)(x-3+i)
Distributing the last two parenthesis first is always the best way to start off
(x-3-i)(x-3+i) has (x-3) in common so it can be separated to
(x-3)^2 + (-i)(+i)
(x^2 - 6x + 9) ; (-i)(+i) is always +1
(x^2 - 6x + 9) + 1
(x^2 - 6x + 10)
Now multiply this with (x-4)
x^3 - 6x^2 + 10x
- 4x^2 + 24x - 40
x^3 - 10x^2 + 34x - 40 = f(x)
