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2 years ago

7

The formula for the volume of a sphere is. What is the formula solved for r?

1 answer:

nataly862011 [7]2 years ago

3 0

Answer:

$r = \sqrt[3]{\dfrac{3V}{4 \pi}}$

Step-by-step explanation:

$V = \dfrac{4}{3}\pi r^3$

$\dfrac{4}{3}\pi r^3 = V$

$\pi r^3 = \dfrac{3V}{4}$

$r^3 = \dfrac{3V}{4 \pi}$

$r = \sqrt[3]{\dfrac{3V}{4 \pi}}$

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A person earns 23,000 one year and gets a 5% raise in salary. Calculate the new yearly salary using a percent greater than 100

Kazeer [188]

Answer:

24,150

Step-by-step explanation:

Given that :

Salary earned this year = 23,000

Percentage Raise in salary for the new year = 5%

The new yearly salary can be obtained thus ;

(100% + percentage raise in salary) * salary earned this year

(100% + 5%) * 23,000

105% * 23000

1.05 * 23000

24,150

4 0

3 years ago

Jimmy's backyard is rectangle that is 18 5/6 yards long and 10 2/5 yards wide Jim buy sod in pieces that are 1 1/3 yard long and

g100num [7]

Answer:

111 pieces of soda

Step-by-step explanation:

step 1

Find the area of the rectangular backyard

The area of the rectangular backyard is equal to

$A=LW$

where

$L=18\frac{5}{6}\ yd=\frac{18*6+5}{6}=\frac{113}{6}\ yd$

$W=10\frac{2}{5}\ yd=\frac{10*5+2}{5}=\frac{52}{5}\ yd$

substitute

$A=(\frac{113}{6})(\frac{52}{5})$

$A=\frac{5,876}{30}\ yd^2$

step 2

Find the area of one piece of sod

The area of the rectangular piece of sod is

$A=LW$

where

$L=1\frac{1}{3}\ yd=\frac{1*3+1}{3}=\frac{4}{3}\ yd$

$W=1\frac{1}{3}\ yd=\frac{1*3+1}{3}=\frac{4}{3}\ yd$

substitute

$A=(\frac{4}{3})^2\\\\A=\frac{16}{9}\ yd^2$

step 3

Find the pieces of sod needed

To find out how many whole pieces of sod will Jim need to buy to cover his backyard, divide the area of the backyard by the area of one piece of soda

so

$\frac{5,876}{30} : \frac{16}{9}=\frac{52,884}{480}=110.175$

Round up

111 pieces of soda

8 0

3 years ago

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Jobisdone [24]

Answer:

$s = \frac{9± \sqrt{ - 39} }{4}$

Step-by-step explanation:

$\frac{3(s - 5)}{4 - 3} = \frac{4s \times (s - 3)}{2}$

➡️ $\frac{3(s - 5)}{1} = 2s \times (s - 3)$

➡️ $3s - 15 = 2 {s}^{2} - 6s$

➡️ $3s - 15 - 2 {s}^{2} + 6s = 0$

➡️ $9s - 15 - 2 {s}^{2} = 0$

➡️ $- 2 {s}^{2} + 9s - 15 = 0$

➡️ $2 {s}^{2} - 9s + 15 = 0$

➡️ $s = \frac{ - ( - 9)± \sqrt{( - 9 {)}^{2} - 4 \times 2 \times 15} }{2 \times 2}$

➡️ $s = \frac{9± \sqrt{81 - 120} }{4}$

➡️ $s = \frac{9± \sqrt{ - 39} }{4}$

➡️ $s∉ℝ$

5 0

2 years ago

How did droughts and dust storms add to the problems farmers faced in the 1930s? Check all of the

Klio2033 [76]

Answer:Please add a photo

Step-by-step explanation:

8 0

2 years ago

Write an equation of the line that passes through a pair of points:<br> (-3,1). (-2,-5)

Nat2105 [25]

Answer:

$y=-6x-17$ (B)

Step-by-step explanation:

$y=mx+b\\m=\frac{y_{2}-y_{1} }{x_{2} -x_{1} } = \frac{1--5}{-3--2} = \frac{6}{-1} = -6\\y=-6x+b\\$

Plug in one of the two points for X and Y

(-3,1)

$1=-6(-3)+b\\1=18+b\\b=-17\\\\y=-6x-17$

5 0

2 years ago