Hi guys i need help with answering this question, it says put the following numbers in order greatest to least

Mathematics

2 answers:

mr Goodwill [35]2 years ago

8 0

Answer:

12.47, 12.075, 11 1/4, 11, -12, -12.004, -12.01

Temka [501]2 years ago

6 0

Answer:

Greatest to Least: 12.47, 12.075, 11 1/4, 11, -12, -12.004, -12.01

You might be interested in

For a party, three solid cheese balls with diameters of 2 inches, 4 inches, and 6 inches, respectively, were combined to form a

schepotkina [342]

Answer:

The radius of the new cheese ball formed is approximately 6.603 inches.

Step-by-step explanation:

We are given the following in the question:

Radius of three cheese ball = 2 inches, 4 inches, and 6 inches

They were combined to form a new cheese ball.

Thus, we can write

Volume of three cheese balls = Volume of new cheese ball.

Let r be the radius of new cheese ball.

Volume of sphere =

$\displaystyle\frac{4}{3}\pi r^3$

Putting values, we get:

$\displaystyle\frac{4}{3}\pi r_1^3 + \displaystyle\frac{4}{3}\pi r_2^3 +\displaystyle\frac{4}{3}\pi r_3^3 =\displaystyle\frac{4}{3}\pi r^3\\\\\frac{4}{3}\pi(2^3 + 4^3 + 6^3) = \displaystyle\frac{4}{3}\pi r^3\\\\2^3 + 4^3 + 6^3 = r^3\\\Rightarrow 288 = r^3\\\Rightarrow r = (288)^{\frac{1}{3}}\\\Rightarrow r \approx 6.603$

Thus, the radius of the new cheese ball formed is approximately 6.603 inches.

3 0

2 years ago

Solve 2x+1=-x+7<br> please helpppp ill cash app who helps me ($10)

FromTheMoon [43]

X=2 cashapp: $alexiswilhite03

6 0

3 years ago

Write the equation of the line for a line that passes through (4, 4) and (1, -2).

pshichka [43]

$(\stackrel{x_1}{4}~,~\stackrel{y_1}{4})\qquad (\stackrel{x_2}{1}~,~\stackrel{y_2}{-2}) ~\hfill \stackrel{slope}{m}\implies \cfrac{\stackrel{rise} {\stackrel{y_2}{-2}-\stackrel{y1}{4}}}{\underset{run} {\underset{x_2}{1}-\underset{x_1}{4}}}\implies \cfrac{-6}{-3}\implies 2 \\\\\\ \begin{array}{|c|ll} \cline{1-1} \textit{point-slope form}\\ \cline{1-1} \\ y-y_1=m(x-x_1) \\\\ \cline{1-1} \end{array}\implies y-\stackrel{y_1}{4}=\stackrel{m}{2}(x-\stackrel{x_1}{4}) \\\\\\ y-4=2x-8\implies y=2x-4$