For this case we have that, by definition, the medians of a triangle are the line segments that are drawn from a vertex to the midpoint of the opposite side of the vertex. The medians of a triangle are concurrent at a point.
If we look at the figure, we can discard triangles 3 and 4.
Also, by definition, the median divides the vertex angle into two equal angles.
Thus, the correct option is triangle 1.
Answer:
Triangle 1
For the first part, the answer is choice B) 360. This applies to any polygon and it doesn't have to be an octagon. The sum of the exterior angles of any polygon is always 360 degrees. This is something you should memorize or have on a reference sheet.
For the second part, the answer is choice C) 142 degrees. We have a parallelogram (specifically a rhombus but that doesn't matter) so the adjacent angles are supplementary. This means they add to 180 degrees. Solving x+38 = 180 leads to x = 142
construction of an angle bisector
of 60° into 30°and 30°
Oh boy, here we go again
First we must convert 1 2/3 to an improper fraction. By doing this, we get 5/3 (3/3 + 2/3)
So now we have 273 / 5/3
To divide this easier we can do something that when I learned it was called (keep, change, flip) which basically means keep the first fraction, change the sign from division to multiplication, and flip the second fraction
This now turns into: 273/1 * 3/5
Combine 273 and 3/5
273⋅3/5
Multiply 273
by 3
819/5
is your answer
