The inverse relation of the function f(x)=1/3x*2-3x+5 is f-1(x) = 9/2 + √(3x + 21/4)
<h3>How to determine the inverse relation?</h3>
The function is given as
f(x)=1/3x^2-3x+5
Start by rewriting the function in vertex form
f(x) = 1/3(x - 9/2)^2 -7/4
Rewrite the function as
y = 1/3(x - 9/2)^2 -7/4
Swap x and y
x = 1/3(y - 9/2)^2 -7/4
Add 7/4 to both sides
x + 7/4= 1/3(y - 9/2)^2
Multiply by 3
3x + 21/4= (y - 9/2)^2
Take the square roots
y - 9/2 = √(3x + 21/4)
This gives
y = 9/2 + √(3x + 21/4)
Hence, the inverse relation of the function f(x)=1/3x*2-3x+5 is f-1(x) = 9/2 + √(3x + 21/4)
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Answer:
x=-0.7
Step-by-step explanation:
7x+1.1=-3.8
subtract 1.1 on both sides
7x=-4.9
divide both sides by 7
x=-0.7
Answer:
-2x-24
Step-by-step explanation:
-5x+3x-24 = - 2x-24
Answer:
the graph should be of the line y=5x
Step-by-step explanation:
the x axis should be labeled hours and the y axis should be labeled amount earned or dollars
the coordinates on the graph should be
(1,5) (2,10) (3,15) (4,20) (5,25) (6,30)
I cannot see the answer choices but I hope this information helps you answer the question
