Answer:
3 MIN AND 46 SECONDS. ITHINK BUT DONT QUOTE ME
Step-by-step explanation:
Arc length = 2 π R (C/360)
where:
C is the central angle of the arc
R is the radius of the arc
arc length = 2 π R (137/360) = 2.39R
Answer:
77.2°
Step-by-step explanation:
Consider the triangle JKR.
∠KJR=108.6 (lies on the same line as ∠RJA, angles on a straight line add up to 180)
All the angles in a triangle add up to 180, so:
∠JKR+∠KJR+∠JRK=180
∠JKR+108.6+32.8=180
∠JKR=38.6=∠RKA
Consider ∠RKA. This angle stands on the same arc as ∠RCA.
Since the angle at centre is twice the angle at circumference, 2(∠RKA) = ∠RCA.
2(∠RKA) = ∠RCA
2(38.6)=∠RCA
∠RCA=77.2°
Since the triangles are the same, just flipped that means that all angles and segments are the same as well
I'm not sure if that's the "correct" way to prove it but that's why they're equal
