Answer:
Answer is C.
Step-by-step explanation:
Answer and Step-by-step explanation:
A. 4 inches: An object that's 4 inches is about 2.54 centimeters or 25.4 millimeters. An business envelope is typically about 4 inches by 9 inches for example.
B. 6 feet: A 6 feet object is quite big when compared to just 4 inches. A feet is 12 inches hence 6 feet is 72 inches. A very tall human being is typically 6 feet.
C. 1 meter: A meter is about 39.37 inches hence it is quite big when compared to a feet. A baseball bat is one meter long.
D. 5 yards: A yard is 36 inches hence a bit smaller than a meter. A trampoline could be 5 yards for example
E. 6 centimeters: one centimeter is 0.394 inches hence smaller than an inch. A 6 centimeters object for example is pencil for writing.
F. 2 millimeters: a millimeter is 0.0394 inches hence smaller than a centimeter and an inch. An orange seed could be 2 millimeters long
G. 3 kilometers: one kilometer is 39370.079 inches hence a kilometer is bigger than inches, meter, feet, yards, centimeters, millimeters. A very big tree could be 3 kilometers long
The force of 10 pounds is made up of the horizontal components of the 8 and 5 pound forces
8 cos 30 + 5 cos 52 = 10
so your answer is 30 degrees
Answer:
a) y = 1/2x + 5/2
y = 2/5x + 29/5
b) hair will be 19 inches for both at 33 months
Step-by-step explanation:
a) rate of growth of friend's hair: (3, 4) (8, 6.5)
(6.5 - 4) ÷ (8 - 3) = 2.5/5 or 1/2
find the y-intercept of equation for growth of friend's hair:
y = mx + b
4 = 1/2(3) + b
4 = 3/2 + b
8/2 - 3/2 = b
5/2 = b
equation for growth of friend's hair:
y = 1/2x + 5/2
rate of growth of cousin's hair: (3, 7) (8, 9)
(9 - 7) ÷ (8 - 3) = 2/5
find the y-intercept of equation for growth of cousin's hair:
y = mx + b
9 = 2/5(8) + b
9 = 16/5 + b
45/5 - 16/5 = b
29/5 = b
equation for growth of cousin's hair:
y = 2/5x + 29/5
b) y = 1/2x + 5/2
y = 2/5x + 29/5
1/2x + 5/2 = 2/5x + 29/5
5/10x + 25/10 = 4/10x + 58/10
1/10x = 33/10
10x = 3300
x = 33
Answer :
(x–30) (x-10)
Given equation :
• x² - 40x + A
when A = 300
1. Use the sum-product pattern
x²- 40x + 300
x²−10x−30x+300
2. Common factor from the two pairs
x² – 10x-30x+300
x(x−10)−30(x−10)
3. Rewrite in factored form
x(x−10)−30(x−10)
(x-30) (x-10)
