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Vladimir [108]
3 years ago
15

2. A force of 20 N acts upon a 5 kg block. Calculate the acceleration of the object.

Mathematics
2 answers:
galina1969 [7]3 years ago
8 0

Answer:

Step-by-step explanation:

force=mass × acceleration

20=5×a

a=20/5=4 m/s²

mezya [45]3 years ago
6 0
I’m pretty sure it’s 20/5
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A ladder is 10 feet long and rests on a wall. The base of the ladder is 5 feet from the wall. Determine how high the ladder touc
mr Goodwill [35]

Answer:

8.66

Step-by-step explanation:

8 0
3 years ago
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△ABC  is a right triangle with right angle C. Side AC is 6 units longer than side BC . If the hypotenuse has length 52–√ units,
Evgesh-ka [11]

Answer:

AC = 7.12 units

Step-by-step explanation:

A right triangle has two legs and a hypotenuse. The hypotenuse is opposite the right angle. As Angle C is the right angle, then the triangle can be constructed as shown in the picture attached. The sides of the triangle have a relationship known as the Pythagorean Theorem a² + b² = c². In the theorem, the legs of the triangle are a and b while the hypotenuse is c. Substitute a = x, b = x+6, and c = √52. Simplify and solve.

a² + b² = c²

x² + (x+6)² = √52²

x² + x² + 12x + 36 = 52

2x² + 12x - 16 = 0

You can use the quadratic formula to solve by substituting a = 2, b = 12, and c = -16.

The quadratic formula is x=\frac{-b+/-\sqrt{b^2-4ac} }{2a}.

Substitute and you'll have:

x=\frac{-b+/-\sqrt{b^2-4ac} }{2a} =\frac{-12+/-\sqrt{12^2-4(2)(-16)} }{2(2)}=\frac{-12+/-\sqrt{144+128} }{4)}

\frac{-12+/-\sqrt{272} }{4}=\frac{-12+/-16.5 }{4} = 1.12, 7.13

Only 1.12 is a solution since 7.13 will not satisfy the Pythagorean theorem

Side AC is 6 units longer than side BC. This means x = BC and AC = x + 6.

AC = 1.12 + 6 = 7.12

6 0
3 years ago
Can someone help me please!!!
Morgarella [4.7K]

Answer: P=1200x+35000

Step-by-step explanation:

Given: A town's population has been growing linearly. In 2003, the population was 35000, and the population has been growing by 1200 (constant rate of change) people each year.

The equation of a line is given by :-

y=mx+c, where m is the slope ( constant rate of change) and c is the initial value of the function.

From the given statement , we have the equation for the population x years after 2003 :-

P=1200x+35000

6 0
3 years ago
A point on the terminal side of an acute angle in standard position is (1, 2 √2). Find the cosine value of this angle.
kozerog [31]

Answer:

cos\theta=1/3

Step-by-step explanation:

The point at the terminal side of an acute angle is given by (1, 2\sqrt{2} ).

That is,

x = 1 and y= 2\sqrt{2} .

Let r be the length of line segment drawn from the origin to the point and is given by the formula:

r = \sqrt{x^{2} + y^{2}}

Substituting the values of x and y into r,

r = \sqrt{1^{2} + (2\sqrt{2} )^{2}}

r = \sqrt{1 + 8}

r = \sqrt{9}

Thus, r=3

Also, cos\theta is given by:

cos\theta = x/r\\

Substituting values of x and r,

cos\theta = 1/3\\

4 0
3 years ago
SOMEONE HELP ME PLEASEEE
Makovka662 [10]

Answer:

I would say A

Step-by-step explanation:

4 0
3 years ago
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