5x^2y is the greatest common factor
Check the one-sided limits:
If <em>f(x)</em> is to be continuous at <em>x</em> = 5, then these two limits should have the same value, which means
5<em>k</em> = 200
<em>k</em> = 200/5
<em>k</em> = 40
Answer:
x = 28
Step-by-step explanation:
let us take three consecutive numbers be (x + 1), (x + 2) and (x + 3)
Now,
The sum of three consecutive integers is 90
i.e.,
(x + 1) + (x + 2) + (x + 3) = 90
x + 1 + x + 2 x + 3 = 90
3x + 6 = 90
3x = 90 - 6
3x = 84
x = 84/3
x = 28
x = 28Thus, The value of x is 28
<h2>
<em><u>VERIFICATION</u></em><em><u>:</u></em></h2>
(x + 1) + (x + 2) + (x + 3) = 90
(28 + 1) + (28 + 2) + (28 + 3) = 90
28 + 1 + 28 + 2 + 28 + 3 = 90
90 = 90
Y² + 10z - 10y - yz = (y - 10)(y - z)
