Thus L.H.S = R.H.S that is 2/√3cosx + sinx = sec(Π/6-x) is proved
We have to prove that
2/√3cosx + sinx = sec(Π/6-x)
To prove this we will solve the right-hand side of the equation which is
R.H.S = sec(Π/6-x)
= 1/cos(Π/6-x)
[As secƟ = 1/cosƟ)
= 1/[cos Π/6cosx + sin Π/6sinx]
[As cos (X-Y) = cosXcosY + sinXsinY , which is a trigonometry identity where X = Π/6 and Y = x]
= 1/[√3/2cosx + 1/2sinx]
= 1/(√3cosx + sinx]/2
= 2/√3cosx + sinx
R.H.S = L.H.S
Hence 2/√3cosx + sinx = sec(Π/6-x) is proved
Learn more about trigonometry here : brainly.com/question/7331447
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First one: false
second one: false
third one: false
fourth one: true
The formula of a slope:
We have the points (0, -2) and (6, 0).
Substitute:
<h3>Answer: A. 1/3</h3>
Answer:
50 feet
Step-by-step explanation:
Perimeter is the sum of all of the lengths of the sides.
A triangle has three sides, and three lengths are given, therefore all the sides are given.
The sum of the sides is 20 + 20 + 10 = 50
So the Perimeter is 50 feet
