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Tresset [83]
2 years ago
9

Find three consecutive numbers whose sum is 1020

Mathematics
2 answers:
krok68 [10]2 years ago
6 0

what's up? the answer to this is 339+340+341

best of luck with your studies

LUCKY_DIMON [66]2 years ago
6 0

Answer: 339 + 340 + 341 = 1020


Step-by-step explanation:

3X + 3 = 1020
3X + 3 - 3 = 1020 - 3
3X = 1017
3X/3 = 1017/3
X = 339

Which means that the first number is 339, the second number is 339 + 1 and the third number is 339 + 2. Therefore, three consecutive integers that add up to 1020 are 339, 340, and 341.

339 + 340 + 341 = 1020


<em>_Hope that helped_</em>

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Equating the first derivative to zero, we get,

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Thus, the maximum concentration of the antibiotic during the first 12 hours is 1.185 \mu g/mL at t= 2 hours.

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