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3 years ago

Please helpppp

Mathematics

2 answers:

scoray [572]3 years ago

8 0

$\huge{ \fbox \color{cyan}{Answer}}$

$\tt \implies \: P \: \rightarrow \: 0.71 \\ \\ \\ \tt \: \: \: { \underline { \green{Solution}}} :$

$\tt \bf \: \: Given : \: \: Grade \: \: \: \: \: \: \: frequency$

$\therefore \tt Total \: \: number \: \: of \: \: students \: \: are \: \: 35$

$\tt \bf \underline{ATQ} : A \: \: student \: \: earn \: \: a \: \: Grade \: \: of \: \: B \: or \: C \:$

$\tt \rightarrow \: Grade \: B \: + \: Grade \: C \: \: = 10 + 15 = 25$

$\sf \: \text{\blue{ Apply formula}} :$

$\tt \: \circ \: Probability =( \frac{number \: of \: favourable \: outcome}{total \: number \: of \: outcomes} )$

$\tt \: \rightarrow \: p(grade \: \: b \: \: or \: \: c) = \cancel \frac{25}{35} = \cancel \frac{5}{7} = 0.714$

$\tt \: round \: to \: nearest \: \: hunderath$

$\tt \bf \implies \: \fbox{ \pink{0.71}}$

tamaranim1 [39]3 years ago

4 0

$\huge{ \fbox {\colorbox{cyan}{Answer}}} \\ \\ \tt \implies \: P \: \rightarrow \: 0.71 \\ \\ \\ \tt \: \: \: { \underline { \green{Solution}}} : \\ \\ \tt \bf \: \: Given : \: \: Grade \: \: \: \: \: \: \: frequency \\ \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: A \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: 5 \\ \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: B \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: 10 \\ \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: C \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: 15 \: \\ \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: D \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: 3 \: \\ \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: F \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: 2 \: \\ \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: - - - - \\ \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: 35 \\ \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: - - - - \\ \\ \: \therefore \tt \: Total \: \: number \: \: of \: \: students \: \: are \: \: 35 \\ \\ \: \tt \bf \underline{ATQ} : A \: \: student \: \: earn \: \: a \: \: Grade \: \: of \: \: B \: or \: C \: \\ \tt \rightarrow \: Grade \: B \: + \: Grade \: C \: \: = 10 + 15 = 25 \\ \\ \sf \: \text{\blue{ Apply formula}} : \\ \\ \tt \: \circ \: Probability =( \frac{number \: of \: favourable \: outcome}{total \: number \: of \: outcomes} ) \\ \\ \tt \: \rightarrow \: p(grade \: \: b \: \: or \: \: c) = \cancel \frac{25}{35} = \cancel \frac{5}{7} = 0.714 \\ \\ \: \tt \: round \: to \: nearest \: \: hunderath \\ \\ \: \: \tt \bf \: \: \: \implies \: \fbox{ \pink{0.71}}$

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