I believe that it is C, mind you I could’ve got it wrong. It’s been awhile since I’ve done that kind of math.
Answer:
we reject H₀
Step-by-step explanation: Se annex
The test is one tail-test (greater than)
Using α = 0,05 (critical value ) from z- table we get
z(c) = 1,64
And Test hypothesis is:
H₀ Null hypothesis μ = μ₀
Hₐ Alternate hypothesis μ > μ₀
Which we need to compare with z(s) = 2,19 (from problem statement)
The annex shows z(c), z(s), rejection and acceptance regions, and as we can see z(s) > z(c) and it is in the rejection region
So base on our drawing we will reject H₀
Answer:
6x+12
Step-by-step explanation:
This is an equivalent expression as all I did was simplify the expression using the distributive property. (6(x)) + (6(2)) = (6x) + (12) = 6x + 12
shown in reverse to prove this is equivalent would look like this. 6x+12 = (6(x)) + (6(2)) = 6(x+2)
Because the gcf is 12 and the lcm is 1000000000000000000000000000000000000000000000000000
So if we have 1/4 gallon of honey. We need to divide it by 3 to find how much is in each loaf. 1/4 ÷ 3/1 = 1/4(1/3) = 1/12.
She used 1/12 gallon for 1 loaf.
Let me know if you have any questions
