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3 years ago

Solve for x. Please help

Mathematics

1 answer:

nata0808 [166]3 years ago

4 0

Answer:

In the pic

Step-by-step explanation:

If you have any questions about the way I solved it, don't hesitate to ask me in the comments below ÷)

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In each triangle below, name the type of line segment that CD is.

bulgar [2K]

There is no picture?

4 0

2 years ago

Use the Chain Rule to find the indicated partial derivatives. z = x^4 + xy^3, x = uv^4 + w^3, y = u + ve^w Find : ∂z/∂u , ∂z/∂v

k0ka [10]

I'll use subscript notation for brevity, i.e. $\frac{\partial f}{\partial x}=f_x$ .

By the chain rule,

$z_u=z_xx_u+z_yy_u$

$z_v=z_xx_v+z_yy_v$

$z_w=z_xx_w+z_yy_w$

We have

$z=x^4+xy^3\implies\begin{cases}z_x=4x^3+y^3\\z_y=3xy^2\end{cases}$

and

$\begin{cases}x=uv^4+w^3\\y=u+ve^w\end{cases}\implies\begin{cases}x_u=v^4\\x_v=4uv^3\\x_w=3w^2\\y_u=1\\y_v=e^w\\y_w=ve^w\end{cases}$

When $u=1,v=1,w=0$ , we have

$\begin{cases}x(1,1,0)=1\\y(1,1,0)=2\end{cases}\implies\begin{cases}z_x(1,2)=12\\z_y(1,2)=12\end{cases}$

and the partial derivatives take on values of

$\begin{cases}x_u(1,1,0)=1\\x_v(1,1,0)=4\\x_w(1,1,0)=0\\y_u(1,1,0)=1\\y_v(1,1,0)=1\\y_w(1,1,0)=1\end{cases}$

So we end up with

$\boxed{\begin{cases}z_u(1,1,0)=24\\z_v(1,1,0)=60\\z_w(1,1,0)=12\end{cases}}$

3 0

3 years ago

stion 1 OT 5A researcher recorded the number of swans and the number of ducks in a lake every month. Function s represents the n

Anon25 [30]

Given functions are

$s(n)=2(1.1)^n+5_{}$ $d(n)=4(1.08)^n+3$

The total number of ducks and swans in the lake after n months can be determined by adding the functions s(n) and d(n).

$t(n)=s(n)+d(n)$

$t(n)=(2(1.1)^n^{}+5)+(4(1.08)^n+3)$

$t(n)=2(1.1)^n+5+4(1.08)^n+3$

$t(n)=2(1.1)^n+4(1.08)^n+5+3$

$t(n)=2(1.1)^n+4(1.08)^n+8$

Taking 2 as common, we get

$t(n)=2\lbrack(1.1)^n+2(1.08)^n+4\rbrack$

Hence The total number of ducks and swans in the lake after n months is

$t(n)=2\lbrack(1.1)^n+2(1.08)^n+4\rbrack$

8 0

1 year ago

1.3 lesson help please

Airida [17]

Answer:

1. 125

2. 25

3. 40

4. 39

First question:

(15-10)^2 + (15-5)^2

parentheses first to get 5^2 + (15-5)^2

exponents next to get 25 + (15-5)^2

parentheses again 25 + 10^2

exponents again 25 + 100 = 125

Second question:

simplify the exponents (3 *3) + (4 * 4) + (2 * 2) to get 9 + 16 + 4 = 29

Third question:

simplify in the parentheses 6 1/7 - 1/7 = 6

divide 60 by 6 to get 10

multiply 10 by 4 to get 40!

Fourth question:

simplify the fractions to get 1/3 + 8/3 = 3

multiply the 3 by 13 to get 39

7 0

2 years ago

Read 2 more answers

What is the distance between (-2 1/2, -3) and (1, -3)

Igoryamba

Answer:

Step-by-step explanation:

(-2 1/2, -3) = (-5/2 , -3) & (1, -3)

$Distance=\sqrt{(x_{2}-x_{1})^{2}+(y_{2}-y_{1})^{2}}\\\\ =\sqrt{(1-[\frac{-5}{2}])^{2}+(-3-[-3])^{2}}\\\\ =\sqrt{(1+\frac{5}{2})^{2}+(-3+3)^{2}}\\\\ =\sqrt{(\frac{7}{2})^{2}} \\\\=\frac{7}{2}\\\\=3\frac{1}{2}$

4 0

3 years ago

Read 2 more answers