$\bf ~~~~~~~~~~~~\textit{distance between 2 points}
\\\\
A(\stackrel{x_1}{-1}~,~\stackrel{y_1}{5})\qquad 
B(\stackrel{x_2}{4}~,~\stackrel{y_2}{1})\qquad \qquad 
% distance value
d = \sqrt{( x_2- x_1)^2 + ( y_2- y_1)^2}
\\\\\\
AB=\sqrt{[4-(-1)]^2+[1-5]^2}\implies AB=\sqrt{(4+1)^2+(1-5)^2}
\\\\\\
AB=\sqrt{5^2+(-4)^2}\implies AB=\sqrt{41}$

4 0

3 years ago

What is the perimeter of ABC, shown? A. 18.83 B. 204.7 C. 29.04 D. 34.5

sweet-ann [11.9K]

The answer is C. 29.04
You use the Pythagorean theorem for the diagonal side because it’s a right triangle then you add all the sides and get C

8 0

3 years ago

Read 2 more answers

What is 7035 divided by 38??

alexdok [17]

The answer is 185 ....................

8 0

3 years ago

Read 2 more answers

Please answer hurry!!!!

lutik1710 [3]

The best way to solve this problem is by plugging in each answer choice for both equations and seeing which one works. You can already see that choice A doesn't work because -1 is not greater than or equal to 4. That means you just need to test choices B and C!

Choice B (4, -2)
$x + y \geq 6\\
4 + -2 \geq 6\\
2 \geq 6 
$
2 is not greater than or equal to 6, so choice B doesn't work.

Choice C (4, 2)
$x + y \geq 6\\ 
4 + 2 \geq 6\\ 
6 \geq 6 \\\\
x \geq 4\\
4 \geq 4$
Since 6 is equal to 6 and 4 is equal to 4, choice C works!

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Answer: C) (4, 2)

6 0

3 years ago