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2 years ago

Which set of ordered pairs could represent a linear function (please help!!)

Mathematics

2 answers:

Sonbull [250]2 years ago

5 0

Answer:

Step-by-step explanation:

Linear Function- points on a graph that make up a straight line negative or positive 

I used a graphing calculator and tried every possible one and C is the only one that made a perfect straight line.

hope this helps ya! <3 me if it does

vlabodo [156]2 years ago

4 0

The answer is A- (3,5), (5,1), (7,-2), (9,-6)

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What is 2(d+9) expression

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If asking to simplify 2d + 18

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3 years ago

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Christine's gross monthly salary at her job

jonny [76]

Answer:

$2587.87 per month

Step-by-step explanation:

The listed deductions are ...

25% withheld for federal income tax
9.3% withheld for California state income tax
6.2% withheld for Social Security tax
1.45% withheld for Medicare Tax
0.9% withheld for SDI- Disability Insurance
5% goes into her retirement 401K account
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The percentages have a total of ...

25 +9.3 +6.2 +1.45 +0.9 +5 = 47.85 . . . percent

So, Christine's take-home pay is ...

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3 years ago

CAN SOMEONE PLZZ HELP WIT THIS!!!!!

Shtirlitz [24]

Answer:

Step-by-step explanation:

b and a=40⁰ so if b+c is supplementary they equal 180⁰ together so 180-40= 150⁰

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2 years ago

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Convert 7.2 ⋅ 10−3 to standard form. (3 points) need help ASAP

zhenek [66]

Answer:

7.2x10^-3--->.0072

Step-by-step explanation:

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2 years ago

What are the coordinates of the endpoints of the midsegment for △DEF that is parallel to DE¯¯¯¯¯?

Readme [11.4K]

Answer:

The endpoints of the midsegment for △DEF that is parallel to DE, are (-1,3.5) and (-1,2).

Step-by-step explanation:

If a line connecting the midpoint of two sides and parallel to the third side of the triangle, then it is called a midsegment.

From the given figure it is noticed that the vertices of the triangle are D(1,4), E(1,1) and F(-3,3).

If the midsegment is parallel to DE, then the end points of the midsegment are mid point of DF and EF.

Midpoint formula.

$Midpoint=(\frac{x_1+x_2}{2},\frac{y_1+y_2}{2})$

Midpoint of DF,

$Midpoint=(\frac{1-3}{2},\frac{4+3}{2})$

$Midpoint=(-1,3.5)$

Midpoint of EF,

$Midpoint=(\frac{1-3}{2},\frac{1+3}{2})$

$Midpoint=(-1,2)$

Therefore the endpoints of the midsegment for △DEF that is parallel to DE, are (-1,3.5) and (-1,2).

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2 years ago