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Dima020 [189]
2 years ago
12

(b) 3 - 2w 29 What is the answer

Mathematics
1 answer:
Alik [6]2 years ago
8 0

Answer:

-2w^{29} +3

Step-by-step explanation:

Let's simplify step-by-step.

3−2w29

=3+−2w29

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Stells [14]

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A

Step-by-step explanation:

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3 years ago
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Please help with #35 I don’t get it and I’m really stressed
skad [1K]

Don't let it get to ya. If they didn't think you're capable of answering this question, they wouldn't ask you. So they know your abilities better than you do.

We don't know the unknown number, so in order to discuss it, we have to give it some kind of a name. We could call it 'x', 'y', 'Ana, 'Q', or 'Ralph'. Let's call it 't'.

The unknown number . . . . . t

Five times the number . . . . . 5t

Nine less than five times the number . . . . . 5t - 9 . Hold on to this quantity.

Twice the number . . . . . 2t .

Three more than twice the number . . . . . 2t + 3. Hold on to this quantity too.

The question says that these two quantities are equal. So the equation is

5t - 9 = 2t + 3 . This is the equation in both choices 'c' and 'd' . I guess we'll have to solve it to find out which choice is the correct one.

The equation is . . . . . 5t - 9 = 2t + 3

Add 9 to each side . . . . . 5t = 2t + 12

Subtract 2t from each side . . . 3t = 12

Divide each side by 3 . . . . . t = 4 .

It looks like choice-d is the winner.

3 0
3 years ago
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The difference when 7 less than a number is subtracted from twice the number is 12. What is the number?
Softa [21]
2n-(n-7)=12
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6 0
3 years ago
The proportion of brown M&amp;M's in a milk chocolate packet is approximately 14%. Suppose a package of M&amp;M's typically cont
marshall27 [118]

Answer:

Kindly check explanation

Step-by-step explanation:

Given the scenario above :

A) State the random variable.

The random variable is the p opoertion of brown M&M's in a milk chocolate packet.

B.) Argue that this is a binomial experiment.

Each trial is independent for a total number of 52 trials with a set probability of success at 0.14

C) probability that 6 M&M's are brown:.

P(x) = nCx * p^x * (1-p)^(n-x)

p = 0.14 ; (1 - p) = 0.86 ; n = 52 ; x = 6

P(x = 6) = 52C6 × 0.14^6 × 0.86^46

= 20358520 × 0.00000752954 × 0.00097035078

= 0.1487

D) P(x =25)

P(x = 25) = 52C25 × 0.14^25 × 0.86^27

= 477551179875952 × 449.987958058*10^(-24) × 0.01703955245

= 0.00000000366

E) P(x = 52)

P(x = 52) = 52C52 × 0.14^52 × 0.86^0

= 1 × 3968.78758299*10^(-48) × 1

= 3968.78758299*10^(-48)

F) yes it would be unusual, because such probability is extremely low. However, if a huge or substantial number of trials such may occur

3 0
3 years ago
Please help!! I NEED IT VERY BADLY
I am Lyosha [343]

Answer:

3/4

Step-by-step explanation:

tan A =opposite/adjacent = 6/8 =3/4

Hope this helps

Have a good day

6 0
3 years ago
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