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wariber [46]
2 years ago
12

Someone plss help me!!!

Chemistry
1 answer:
NikAS [45]2 years ago
4 0

Answer:

d. Cl2

sorry if I'm wrong

Cl2, as shown in the picture should have electrons in both the atoms but, in the question, the electrons are only in one of the atoms.

hope it helps :)

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What are two examples of homogeneous<br>​
Andrei [34K]

Answer:

two examples are blood and soapy water.

Explanation:

7 0
3 years ago
Question 2
Alenkinab [10]

Answer:

1.53 atm

Explanation:

From the question given above, the following data were obtained:

Volume = constant

Initial pressure (P₁) = stp = 1 atm

Initial temperature (T₁) = 273 K

Final temperature (T₂) = 144 °C = 144 °C + 273 = 417 K

Final pressure (P₂) =?

Since the volume is constant, the final pressure can be obtained as follow:

P₁ / T₁ = P₂ / T₂

1 / 273 = P₂ / 417

Cross multiply

273 × P₂ = 417

Divide both side by 273

P₂ = 417 / 273

P₂ = 1.53 atm

Therefore, the final pressure (i.e the pressure inside the hot water bottle) is 1.53 atm.

8 0
3 years ago
A certain reaction with an activation energy of 205 kj/mol was run at 485 k and again at 505 k . what is the ratio of f at the h
lapo4ka [179]
Arrhenius' Law relates activation energy, Ea, rate constant, K, and temperature, T as per this equation:

K (T) = A * e ^ (-Ea / RT), where R is the universal constant of gases and A is a constant which accounts for collision frequency..

Then you can find the ration between K's at two different temperatures as:

K1 = A * e ^ (-Ea / RT1)

K2 = A* e ^(-Ea / RT2)

=> K1 / K2 = e ^ { (-Ea / RT1) - Ea / RT2) }

=> K1 / K2 = e ^ {(-Ea/ R ) *( 1 / T1 - 1 T2) }

=> K1 / K2 = e^ { (-205,000 j/mol / 8.314 j/mol*k )* ( 1 / 505K - 1/ 485K) }

=> K1 / K2 = e ^ (2.0134494) ≈ 7.5

Answer: 7.5




8 0
3 years ago
8)
Rina8888 [55]
B mass but not of charge
7 0
3 years ago
If 56 grams of notrogen are used up by the reaction, how many grams of amonia will be produced? 1N2+3H2--&gt; 2NH3
djverab [1.8K]
1 mole of N2 produces 2 moles of NH3
OR...
14 x 2 grams of N2 produces 2(14 +3) grams of NH3
1 gram of N2 produces 34/28 grams of NH3
therefore, 56 grams produce (34/28 )x 56 =68 grams of NH3 

the answer thus would be 68 grams of NH3
5 0
3 years ago
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