Answer:
2200 g
Explanation:
Data Given:
no. of moles of Ba₃N₂ = 5 moles
mass of Ba₃N₂ = ?
Solution:
Formula used
no. of moles = mass in grams / molar mass
To find mass rearrange the above equation:
mass in grams = no. of moles x molar mass. . . . . . (1)
molar mass of Ba₃N₂
molar mass of Ba₃N₂ = 3(137.3) + 2(14)
molar mass of Ba₃N₂ = 412 + 28
molar mass of Ba₃N₂ = 440 g/mol
Put values in equation 1
mass in grams = 5 moles x 440 g/mol
mass in grams = 2200 g
So,
mass of Ba₃N₂ = 2200 g
Answer:
Explanation:
Hello!
In this case, since the dilution processes are characterized by the decrease of the original stock solution by holding the moles constant and therefore modify the volume, for the described dilution we can write:
Whereas we are asked to compute the volume of the original solution; thus, we can solve for it as shown below:
Best regards!
The most common way of preventing bumping is by adding one or two boiling chips to the reaction vessel. However, these alone may not prevent bumping and for this reason it is advisable to boil liquids in a boiling tube, a boiling flask, or an Erlenmeyer flask.
Answer:
2.62 atm
Explanation:
1 atm = 14.6959 psi
38.5 / 14.6959 = 2.62 atm
Answer:
1. C- Three.
2. A- Methionine
3. D- Translocation.
4. C- OH.
5. A - 5'
6. A - 3' carbon
7. A. adenine and guanine
Explanation:
1. A codon is a group of three nucleotide sequence that encodes or specifies an amino acid. This means that, during translation (second stage of gene expression), when a CODON is read, an amino acid is added to the growing peptide chain.
2. The codon that initiates the translation process is called a start codon. It has a sequence: AUG and it specifies Methionine amino acid. Hence, during translation where a tRNA binds to the mRNA codon to read it and add its corresponding amino acid, a tRNA with a complementary sequence of AUG (start codon) binds to it and carries Methionine amino acid.
3. Translocation is a process during translation whereby the mRNA-tRNA moeity moves forward in the ribosome to allow another codon to move into the vacant site for translation process to continue.
4. The sugar component of a nucelotide that makes up the nucleic acid (DNA or RNA) i.e. ribose or deoxyribose, contains an hydroxyll functional group (-OH).
5. A nucleotide consists of a pentose (five carbon) sugar, phosphate group and a nitrogenous base. The phosphate group (PO43-) is attached to the 5' carbon of the sugar molecule.
6. The free hydroxyll group (-OH) of the five carbon sugar molecule in DNA is attached to its 3' carbon.
7. Nitrogenous bases are the third component of a nucleotide, the other two being pentose sugar and phosphate group. The nitrogenous bases are four viz: Adenine, Guanine, Cytosine, and Thymine. These bases are classified into Purines and Pyrimidines based on the similarity in their structure. Adenine (A) and Guanine (G) are Purines because they possess have two carbon-nitrogen rings, as opposed to one possessed by Pyrimidines (Thymine and Cytosine).
