What is the volume at stp of 720.0 ml of a gas collected at 20.0 °c and 3.00 atm pressure?

1 answer:

5 0

Combined gas law is
PV/T = K (constant)

P = Pressure
V = Volume
T = Temperature in Kelvin

For two situations, the combined gas law can be applied as,
P₁V₁ / T₁ = P₂V₂ / T₂

P₁ = 3.00 atm P₂ = standard pressure = 1 atm
V₁ = 720.0 mL T₂ = standard temperature = 273 K
T₁ = (273 + 20) K = 293 K

By substituting,
3.00 atm x 720.0 mL / 293 K = 1 atm x V₂ / 273 K
V₂ = 2012.6 mL

hence the volume of gas at stp is 2012.6 mL

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<h3>Mole-mass relationships:</h3>

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