Step 1: 1
(((x3) - (2•5x2)) + 29x) - 30 = 0
Step 2 2.1 x3-10x2+29x-30 is not a perfect cube
Step 3 Factoring: x3-10x2+29x-30
Thoughtfully split the expression at hand into groups, each group having two terms :
Group 1: 29x-30
Group 2: -10x2+x3
Pull out from each group separately :
Group 1: (29x-30) • (1)
Group 2: (x-10) • (x2)
Hello,
f(x)=6x^3+18x²+12x=6x(x²+3x+2)
=6x(x²+x+2x+2)=6x((x(x+1)+2(x+1))
=6x(x+1)(x+2)
Zeros are 0,-1,-2
Answer:
i hope this helps :)
Step-by-step explanation:
pic below
Hi!
The answer is :
(y+2) * (y+9) = y^2 + 2y + 9y + 18 = y^2 + 11y + 18
Hope this helps!