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3 years ago

15

Is prime a composite number, a prime number, both or neither? Pease explain.

1 answer:

Annette [7]3 years ago

5 0

Composite number is made up of 2 or more prime numbers
a prime number is only made up of itself and 1

composite and prime numbers are like oposites

a prime is not a composite but it is a prime number
confusing quesiton

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Mrs. Low has 12 bags, each containing 25 sweets. She divides the sweets among 30 boys equally. How many sweets does each boy get

irakobra [83]

Each boy gets 10 sweets.

12×25=300÷30=10//

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4 years ago

Determine whether 96 is divisible by 3

aleksandr82 [10.1K]

96 divided by 3 is 32
Therefor, it is divisible by 3
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3 years ago

Read 2 more answers

Raoul has to finish a 473-page book in a week. He decides to read the same number of pages each weekday and 30 extra pages on Sa

hodyreva [135]

Answer:

$59$ pages

Step-by-step explanation:

Variable:

x = number of pages he has to read on a weekday

x + 30 = The number of pages read on Saturday and Sunday

$5x+2(x+30) = 473$

$==> 5x + 2x + 60 = 473$

$==> 7x =413$

$==> x = 59$

Meaning that Raoul has to read 59 pages on Wednesday

6 0

3 years ago

G = 1, h = 2<br><br> 7 + g − 8 + 2h + 4g

Slav-nsk [51]

Answer:

7+1-8+2(2)+4(1)

= -1+4+4

=7

5 0

2 years ago

Y=-x^2+2x+10<br> y=x+2<br><br> Substitution <br> Please show your work<br> Need ASAP

erik [133]

Answer:

The solutions of the system of equations are the points

$(\frac{1-\sqrt{33}} {2},\frac{5-\sqrt{33}} {2})$

$(\frac{1+\sqrt{33}} {2},\frac{5+\sqrt{33}} {2})$

Step-by-step explanation:

we have

$y=-x^{2} +2x+10$ ----> equation A

$y=x+2$ ----> equation B

Solve the system by substitution

substitute equation B in equation A

$x+2=-x^{2} +2x+10$

solve for x

$-x^{2} +2x+10-x-2=0$

$-x^{2} +x+8=0$

The formula to solve a quadratic equation of the form

$ax^{2} +bx+c=0$

is equal to

$x=\frac{-b\pm\sqrt{b^{2}-4ac}} {2a}$

in this problem we have

$-x^{2} +x+8=0$

so

$a=-1\\b=1\\c=8$

substitute in the formula

$x=\frac{-1\pm\sqrt{1^{2}-4(-1)(8)}} {2(-1)}$

$x=\frac{-1\pm\sqrt{33}} {-2}$

$x=\frac{-1+\sqrt{33}} {-2}$ -----> $x=\frac{1-\sqrt{33}} {2}$

$x=\frac{-1-\sqrt{33}} {-2}$ -----> $x=\frac{1+\sqrt{33}} {2}$

<em>Find the values of y</em>

For $x=\frac{1-\sqrt{33}} {2}$

$y=x+2$

$y=\frac{1-\sqrt{33}} {2}+2$ ----> $y=\frac{5-\sqrt{33}} {2}$

For $x=\frac{1+\sqrt{33}} {2}$

$y=x+2$

$y=\frac{1+\sqrt{33}} {2}+2$ ----> $y=\frac{5+\sqrt{33}} {2}$

therefore

The solutions of the system of equations are the points

$(\frac{1-\sqrt{33}} {2},\frac{5-\sqrt{33}} {2})$

$(\frac{1+\sqrt{33}} {2},\frac{5+\sqrt{33}} {2})$

5 0

3 years ago