Find the measure of x.

It takes Maya 30 minutes to solve 5 logic puzzles ,and it takes Amy 28 minutes to solve logic puzzles use models to show the rat

Alla [95]

Answer:

Maya solve puzzle in 6 minutes per puzzle and Amy solves the puzzle in 7 minutes per puzzle.

Step-by-step explanation:

Given:

For Maya 5 puzzles = 30 minutes

For Amy 4 puzzles = 28 minutes

We need to find the rate at which student solve the puzzle in minutes per puzzle.

Solution:

First we will find the rate of Maya.

5 puzzles = 30 minutes

1 puzzle = Number of minutes for 1 puzzle

By Using Unitary method we get;

Number of minutes for 1 puzzle = $\frac{30}{5}=6\ mins$

Hence Maya requires 6 minutes for 1 puzzle.

Now we will find the rate of Amy.

4 puzzles = 28 minutes

1 puzzle = Number of minutes for 1 puzzle

By Using Unitary method we get;

Number of minutes for 1 puzzle = $\frac{28}{4}=7\ mins$

Hence Maya requires 7 minutes for 1 puzzle.

Hence We can say that Maya solve puzzle in 6 minutes per puzzle and Amy solves the puzzle in 7 minutes per puzzle.

8 0

3 years ago

Read 2 more answers

Please help! I will give you a lot of points if you do and the brainiest!

Anika [276]

Answer:

First truth table:

~q p V ~q ~(p V ~q)

F T F

T T F

F F T

T T F

Second truth table:

~q p V ~q ~(p V ~q)

F T F

Step-by-step explanation:

The ~ operator is a negator (or NOT), such that it is the opposite of the sign.

The first column wants the negation of $q$ , and the values of q are

T, F, T, F, for the columns starting from the top. The negation for the columns are F, T, F, T.

For the second column, The 'V' operator is the OR operator, so a single True, or T will result in a True.

For the first row, not q is F, and T OR F will result in T.

For the second row, not q is T, and T OR T will result in T.

For the third row, not q is F, and F OR F will result in F.

For the fourth row, not q is T, and F OR T will result in T.

In the last column, we must figure out not p OR not q, which we did in the last column, so all we must do is figure out the NOT of values of the last column.

The values of the last column are T, T, F, T, respectively, so the not of the columns will be F, F, T, F.

In the bottom truth table, not q, will be F because the value of q is T. The second column wants p OR not q, and we already know that not q is F, and the value of p is T. T OR F is equal to T. In the last column, the question wants the not of p OR not q, which we did in the last column, so we must figure out the not value of the last column, which is T. The not of T is F.

8 0

3 years ago

Work out the length of the perimeter.

PilotLPTM [1.2K]

Try this option:
According to property such triangle
1. area=0.5*a*b, where a and b - the sides of angle 90°.
Using this equation: 180=0.5*40*b, ⇒ b=9.
2. c²=a²+b², ⇒c=√(9²+40²)=41 - the third side of the triangle;
3. Perimeter=a+b+c=9+40+41=90 cm.

answer: 90 cm.

3 0

3 years ago

8x - 3y, using x = 5 and y = 2

jeka57 [31]

Step 1: plug in 5 and 2 for your X and Y

Step 2: multiply 8*X or in this case 8*5 and you will get 40

Step 3: multiply 3*Y or in this case 3*2 and you will get 6

Step 4: subtract 40-6 and you will get 34

5 0

3 years ago

The hypotenuse of a right angled triangle is 2√13 cm . If the smaller side is increased by 2 cm and the larger side is increased

White raven [17]

Statement:

The hypotenuse of a right angled triangle is 2√13 cm. If the smaller side is increased by 2 cm and the larger side is increased by 3 cm, the new hypotenuse will be √117 cm.

To find out:

The length of the larger side of the right angled triangle.

Solution:

Let us consider x as the smaller side and y as the larger side.

Then, in the right angled triangle,

x² + y² = (2√13)² ...(I) [By Pythagoras Theorem]

Now, if the smaller side is increased by 2 cm, then the smaller side will be (x + 2).

And if the larger side is increased by 3 cm, then the larger side will be (y + 3).

Then, in the new right angled triangle,

(x + 2)² + (y + 3)² = (√117)² [By Pythagoras Theorem]

or, x² + 2 × 2 × x + 2² + y² + 2 × 3 × y + 3² = (√117)²

or, x² + 4x + 4 + y² + 6y + 9 = (√117)²

or, x² + y² + 4x + 6y + 13 = (√117)²

Now, put the value of x² + y² from equation (I),

or, (2√13)² + 4x + 6y + 13 = (√117)²

or, (2 × 2 × √13 × √13) + 4x + 6y + 13 = (√117 × √117)

or, 52 + 4x + 6y + 13 = 117

or, 4x + 6y = 117 - 52 - 13

or, 4x + 6y = 52

or, 4x = 52 - 6y

or, x = $\frac {(52 - 6y)}{4}$ ...(II)

Now, put the value of x of equation (II) in (I),

x² + y² = (2√13)²

or, $\frac {(2704-624y +36y²)}{16}$ + y² = 52

or, $\frac {(2704-624y +36y² + 16y²)}{16}$ = 52

or, 52y²-624y + 2704 = 52 × 16

or, 52y² - 624y + 2704 - 832 = 0

or, 52y² - 624y + 1872 = 0

or, 52(y² - 12y + 36) = 0

or, y²-12y +36 = 0 ÷ 52

or, y²-12y +36 = 0

or, (y)² - 2 × 6 × y + (6)² = 0

or, (y - 6)² = 0

or, y - 6=0

or, y = 6

We have taken y as the length of the larger side of the right angled triangle.

So, the length of the larger side is 6 cm.

Answer:

6 cm

Hope you could understand.

If you have any query, feel free to ask.

6 0

3 years ago