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AlexFokin [52]
2 years ago
5

So if Johnny had 3×6 amount if dish soap. How much dish soap would he have?​

Mathematics
1 answer:
mestny [16]2 years ago
8 0

Answer:

18

Step-by-step explanation:

3x6=6x3=6+6+6=12+6=18

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Which data set is accurate and precise based on a correct value of 30?
Pepsi [2]

Answer:

Set 1: 30, 35, 32, 30, 29

Step-by-step explanation:

Let's first clarify what is accurate and precise:

Precise is based on how close two or more measured values are to each other. While something is said to be accurate, when the standard value values are close, which in our case is 30.

Therefore, we analyze each set:

Set 1: 30, 35, 32, 30, 29

This set is precise and accurate, since 2 values are 30 and all their values are close to each other.

Set 2: 15, 16, 12, 15, 14

This set is precise, because all of its values are close but not accurate.

Set 3: 19, 30, 78, 43, 30

This set is somewhat accurate because there are 2 values of 30, but it is not precise because its values are separate.

Set 4: 30, 30, 67, 12, 90

It is the same case of Set 3.

Therefore the answer is Set 1.

8 0
3 years ago
The points plotted below are on the graph of a polynomial. Which of the
Nady [450]

Answer: -1.1 , 2.4 , 1.51

Step-by-step explanation:

8 0
3 years ago
PLease help!!!!!!!!!!!!!!!!!!!!!!1
schepotkina [342]
4(5x-20)= -20

20x-80= -20
      +80  +80
____________

20x=60
_______
      20

x=3
3 0
3 years ago
Read 2 more answers
A roller coaster is at the top of a 72 m hill and weighs 134 kg. The coaster (at this moment) has____________ energy. Calculate
Inga [223]

Answer:C

Step-by-step explenation: m=134kg,h=72m,g=10m/s

PE=mgh

PE=(134kg)(10m/s^2)(72m)

PE=964800J

5 0
3 years ago
A piece of wire 23 m long is cut into two pieces. One piece is bent into a square and the other is bent into an equilateral tria
AURORKA [14]

Answer:

For maximum area, all of the wire should be used to construct the square.

The minimum total area is obtained when length of the wire is 10m

Step-by-step explanation:

For maximum,  we use the whole length

For minimum,

supposed the x length was used for the square,

the length of the side of the square = x/4m

Area = \frac{x^{2} }{16}

For the equilateral triangle, the length of the side =  \frac{23 - x}{3}

Area = \frac{\sqrt{3} }{4}  a^{2}  = \frac{\sqrt{3} }{4} (\frac{23 - x}{3} )^{2}

Total Area = \frac{x^{2} }{16}  + \frac{\sqrt{3} }{36} (23-x)^{2}

\frac{dA}{dx}  = \frac{x}{8}  -  \frac{\sqrt{3} }{18} (23 - x)\\

\frac{d^{2}A }{dx^{2} }  = \frac{1}{8}  + \frac{\sqrt{3} }{18}  > 0, therefore it is minimum

\frac{dA}{dx}  = 0 \\\\

\frac{x}{8}  -  \frac{\sqrt{3} }{18} (23 - x) = 0\\

x = 10.00m

3 0
3 years ago
Read 2 more answers
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