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3 years ago

What does weighing less on the moon mean for astronauts on the moon?

Physics

1 answer:

AnnyKZ [126]3 years ago

5 0

Answer:

Isaac Newton discovered that as an object's mass increases, the gravitational attraction of that object increases. Thus, the gravitational attraction on the Moon is much less than it is here on Earth, and a person weighs less on the Moon.

hope this helps!

You might be interested in

Which statement is true about an object moving in a circular motion due to centripetal force, F, when the mass is doubled? A. It

Allushta [10]

Force = [Mass x (velocity)^2]/Radius
Therefore,
The mass and the force are directly proportional.If you double the mass,the force will be doubled too.

A. Its centripetal force would be doubled.

3 0

3 years ago

When operated on a household 110.0-V line, typical hair dryers draw about 1650 W of power. We can model the current as a long st

Dimas [21]

Answer:

Current = 15 A

Resistance = 7.33 ohm

Magnetic field = 1.62 x 10^-4 Tesla

Explanation:

V = 110 V, P = 1650 W, r = 1.85 cm,

(a) Let i be the current

P = V x i

i = 1650 / 110 = 15 A

(b) Let R be the resistance

V = i R

R = 110 / 15 = 7.33 Ohm

B = μ0 / 4π x 2i / r

B = 10^-7 x 2 x 15 / 0.0185 = 1.62 x 10^-4 Tesla

5 0

3 years ago

Kate gathered three boxes of the same size made of different materials: glass, clear plastic, and aluminum painted black. She pl

jenyasd209 [6]

Answer:

A. independent variable.

Explanation:

In this experiment, the types of box materials are a(n) independent variable, which is when you purposely change things or control them, hoping for a specific outcome.

4 0

3 years ago

Can someone help me ?

Paraphin [41]

Explanation:

300m÷60s=5m/s

hope this can help maybe

8 0

2 years ago

A water balloon is thrown horizontally at a speed of 2.00 m/s from the roof of a building that is 6.00 m above the ground. At th

Elis [28]

Answer:

The water ballon that was thrown straight down at 2.00 m/s hits the ground first, 0.19 s before the other ballon.

Explanation:

The motions of the two water ballons are ruled by the kinematic equations:

$y=y_0+V_0t-gt^2/2$

We are only interested in the vertical motion, so that equation is all what you need.

1. Water ballon is thrown horizontally at sped 2.00 m/s.

The time the ballon takes to hit the ground is independent of the horizontal speed.

Since 2.00 m/s is a horizontal speed, you take the initial vertical speed equal to 0.

Then:

$y=y_0+V_0t-gt^2/2\\ \\ 0=6.00m-9.8\frac{m}{s^2} t^2/2\\ \\ t=\sqrt{2\times6.00m/9.8\frac{m}{s^2}}\\\\ t=1.11s$

2. Water ballon thrown straight down at 2.00 m/s

Now the initial vertical speed is 2.00 m/s down. So, the equation is:

$0=6.00m-2.00\frac{m}{s}t-9.8\frac{m}{s^2}t^2/2\\ \\ 4.9t^2+2t-6=0\\ \\ t=0.92s$

To solve the equation you can use the quadratic formula.

$t=\frac{-2+/-\sqrt{2^2-4(4.9)(-6)} }{2(4.9)}\\ \\ t=-1.33\\ \\ t=0.92$

You get two times. One of the times is negative, thus it does not have physical meaning.

3. Conclusion:

The water ballon that was thrown straight down at 2.00 m/s hits the ground first by 1.11 s - 0.92s = 0.19 s.

5 0

3 years ago