The water-ice particles forming Saturn's rings are frozen together into a thin sheet that rotates around Saturn like a solid bod
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Answer:
Explanation:
Given values
Mass (m) = 2kg
K = 400 N/M
Compressing it 0.3 m
<u>The law of conservation of energy</u>:
Energy of the spring deformation.
M mass of the block
x spring deformation
Therefore, if block left the spring (x = 0)
Where, Δl is initial spring deformation
<u>The law of conservation of energy</u>:
Where h is height
Cancel mass "m" each side
Distance along incline equals
5.1 m
Explanation:
Let's set the ground as our reference point. Let's also call the dropped ball to be ball #1 and its height above the ground at any time t is given by
(1)
where 10 represents its initial height or displacement of 10 m above the ground. At the same time, the displacement of the second ball with respect to the ground is given by
(2)
At the instant the two balls collide, they will have the same displacement, therefore
or
Solving for t, we get
We can use either Eqn(1) or Eqn(2) to hind the height where they collide. Let's use Eqn(1):