Answer:
B
Explanation:
Newton's second law:
F = ma
The acceleration is Δv/Δt, so:
F = m Δv/Δt
Given m = 1300 kg, Δv = 15 m/s, and Δt = 2 s:
F = (1300 kg) (15 m/s) / (2 s)
F = 9750 N
Answer B.
Pretty fast. Everything looks fast when running past a light pole
Answer:
N = 19.6 N
Explanation:
Given that,
Mass of a block, m = 2000 g
1 kg = 1000 g
It means, 2000 g = 2kg
We need to find the value of normal force on the block on a table. Normal force is balanced by the weight of the block as follows :
N = mg, g is acceleration due to gravity
N = 2 kg × 9.8 m/s²
N = 19.6 N
So, the normal force acting on the block is 19.6 N.
Answer:
a) 0.0324 rad/s²
b) 2.01 rad/s , the final angular speed gets doubled
Explanation:
w₀ = initial angular speed = 0 rad/s
w = final angular speed = 0.16 rev/s = 0.16 (6.28) = 1.005 rad/s
t = time interval = 31 s
α = angular acceleration
final angular speed is given as
w = w₀ + α t
1.005 = 0 + α (31)
α = 0.0324 rad/s²
b)
After the acceleration is doubled
α' = 2 α = 2 (0.0324) = 0.0648 rad/s²
w' = final angular speed
w'₀ = initial angular speed = 0 rad/s
final angular speed is given as
w = w₀ + α t
w = 0 + (0.0648) (31)
w = 2.01 rad/s
yes the final angular speed gets doubled
