Answer:
C=0
Step-by-step explanation:
Answer:
B
Step-by-step explanation:
Data set D does not contain the value 128, which is the median value.
Data set C does not contain the outlier value 91.
Data set A contains value 168, which does not show up on the plot.
The only remaining choice is B.
_____
In order, the data values of set B are ...
... 91, 114, 120, 126, 128, 128 134, 136, 139, 142, 152
The median value of these 11 is the 6th one: 128. The median values of the remaining two sets of 5 are 120 and 139, making these values the quartiles at the ends of the box. The value 91 is more than 1.5 times the IQR (19) below the 1st quartile, so is considered an outlier. (The cutoff is 120-1.5·19=91.5.)
Answer:
504 combos
Step-by-step explanation:
Cannot use digits twice and last is '7'
9 digits for first place choice
8 digits for second place
7 digits for third place
only '7' for fourth place 9 x 8 x7 = 504 combos
first and second part put 0.75, then multiply 0.75 by 2 to get 1.50, then write in the third part 1 and 1/2
hope this helps
Answer:
27,824
Step-by-step explanation:
i just calculated it.
