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madam [21]
3 years ago
13

Erick, Mia, and Isabelle golfed 9 holes. Erick scored 10 more than Mia, and Isabelle scored 16 less than twice Mia's score. Use

the drop-down menus to complete the statements about the expression that represents the scenario. What does the expression x + x + 10 + 2x – 16 represent from the given scenario? What does the variable in the expression represent? What is the expression in simplified form? What is the constant in the simplified expression?
Mathematics
2 answers:
Rama09 [41]3 years ago
5 0
Let Mia's score be x.  Then, Erick scored 10 more than Mia, so his score is x+10.  Isabelle scored 16 less than twice Mia's score, so her score is 2x-16.  We can see that x + x + 10 + 2x - 16 is the sum of these variables, so the expression represents the total of their scores in this scenario.  Moreover, we recall that the variable in the expression, x, represents Mia's score.

To simplify this expression, we add up the variables and the numbers separately, giving us x+x+10+2x-16 = (x+x+2x) + (10-16) = 4x-6.  Therefore, in simplified form, the expression is equal to 4x - 6.  The constant term in an expression is the term not multiplied by a variable, so in this case, it is -6.
deff fn [24]3 years ago
5 0

Answer:

1. The total score of all three players.

2. Mia's score.

3. 4x-6\

4. -6

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660000

Step-by-step explanation:

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1 year ago
A die is rolled. Write each answer as a fraction, decimal, and percent. Show your work.
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Ulleksa [173]

Answer:

\dfrac{5x + 1}{6(x - 2)}

\dfrac{5x + 1}{6x - 12}

Step-by-step explanation:

Fatorizam-se os denominadores.

2x - 4 = 2(x - 2)

3x - 6 = 3(x - 2)

O minimo multiplo comum dos denominadores e

2(3)(x - 2)

\dfrac{x + 1}{2x - 4} + \dfrac{x - 1}{3x - 6} =

= \dfrac{3(x + 1)}{2(3)(x - 2)} + \dfrac{2(x - 1)}{2(3)(x - 2)}

= \dfrac{3(x + 1) + 2(x - 1)}{6(x - 2)}

= \dfrac{3x + 3 + 2x - 2)}{6(x - 2)}

= \dfrac{5x + 1}{6(x - 2)}

= \dfrac{5x + 1}{6x - 12}

4 0
3 years ago
What does the remainder theorem conclude given that f(x)x+3 has a remainder of 11?
Slav-nsk [51]

By the remainder theorem of polynomial division, the complete equation is f(-3) = 11

<h3>How to complete the blanks?</h3>

The equation is given as:

f(x)/x + 3

Set the divisor to 0

x + 3 = 0

Solve for x

x = -3

Given that the quotient has a remainder of 11.

It means that:

f(-3) = 11

Hence, the complete equation is f(-3) = 11

Read more about remainder theorem at:

brainly.com/question/13328536

#SPJ1

5 0
2 years ago
Amy is pulling a wagon with a force of 30 pounds up a hill at an angle of 25°. Give the force exerted on the wagon as a vector a
Fofino [41]

Answer:

Vector (ordered pair - rectangular form)

\vec F = (27.189,12.679)\,[lbf]

Vector (ordered pair - polar form)

\vec F = (30\,lbf, 25^{\circ})

Sum of vectorial components (linear combination)

\vec F = 27.189\cdot \hat{i} + 12.679\cdot \hat{j}\,[N]

Step-by-step explanation:

From statement we know that force exerted on the wagon has a magnitude of 30 pounds-force and an angle of 25° above the horizontal, which corresponds to the +x semiaxis, whereas the vertical is represented by the +y semiaxis.

The force (\vec F), in pounds-force, can be modelled in two forms:

Vector (ordered pair - rectangular form)

\vec F =  \left(\|\vec F\|\cdot \cos \theta, \|\vec F\|\cdot \sin \theta\right) (1)

Vector (ordered pair - polar form)

\vec F = \left(\|\vec F\|, \theta\right)

Sum of vectorial components (linear combination)

\vec {F} = \left(\|\vec F\|\cdot \cos \theta\right)\cdot \hat{i} + \left(\|\vec F\|\cdot \sin \theta \right)\cdot \hat{j} (2)

Where:

\|\vec F\| - Norm of the vector force, in newtons.

\theta - Direction of the vector force with regard to the horizontal, in sexagesimal degrees.

\hat{i}, \hat{j} - Orthogonal axes, no unit.

If we know that \|\vec F\| = 30\,lbf and \theta = 25^{\circ}, then the force exerted on the wagon is:

Vector (ordered pair - rectangular form)

\vec F= \left(30\cdot \cos 25^{\circ}, 30\cdot \sin 25^{\circ}\right)\,[lbf]

\vec F = (27.189,12.679)\,[lbf]

Vector (ordered pair - polar form)

\vec F = (30\,lbf, 25^{\circ})

Sum of vectorial components (linear combination)

\vec F = (30\cdot \cos 25^{\circ})\cdot \hat{i} + (30\cdot \sin 25^{\circ})\cdot \hat{j}\,[N]

\vec F = 27.189\cdot \hat{i} + 12.679\cdot \hat{j}\,[N]

8 0
2 years ago
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