Let
a1=1/40
a2=4/40
a3=9/40
a4=16/40
a5=25/40
a6=?
we know that
a2-a1=4/40-1/40----> 3/40
a3-a2=9/40-4/40-----> 5/40
a4-a3=16/40-9/40----> 7/40
a5-a4=25/40-16/40---> 9/40
the difference is
3/40,5/40,7/40.9/40,....
3/40+[2/40]---> 5/40
5/40+[2/40]---> 7/40
7/40+[2/40]---> 9/40
the next will be
9/40+[2/40]-----> 11/40
so
the next term is 25/40+[11/40]------> 36/40
the answer is
36/40
Answer:
Multiples [10] - 10, 20, 30, 40, 50
Multiples [11] - 11, 22, 33, 44, and 55
<u><em>Find the Even numbers of these multiples</em></u>
Multiples [10]
- - 10 = Even
- - 20 = Even
- - 30 = Not Even
- - 40 = Even
- - 50 = Not Even
- <u><em>10 × 1 = 10</em></u>
- <u><em>10 × 2 = 20</em></u>
- <u><em>10 × 3 = 30</em></u>
- <u><em>10 × 4 = 40</em></u>
- <u><em>10 × 5 = 50</em></u>
Multiples [11]
- - 11 = Not Even
- - 22 = Even
- - 33 = Not Even
- - 44 = Even
- - 55 = Not Even
- <u><em> 11 × 1 = 11</em></u>
- <u><em> 11 × 2 = 22</em></u>
- <u><em> 11 × 3 = 33</em></u>
- <u><em> 11 × 4 = 44</em></u>
- <u><em> 11 × 5 = 55</em></u>
- <u><em> 11 × 6 = 66</em></u>
- <u><em> 11 × 7 = 77</em></u>
- <u><em> 11 × 8 = 88</em></u>
- <u><em> 11 × 9 = 99</em></u>
Step-by-step explanation:
.... I messed up, sorry. I thought that 20 said 11
Answer:
32
Step-by-step explanation:
1) 2x + 3 = 2x + 3
This works because if you solve it, you will get either x = x or 3 = 3 which are always true, so x, can have an infinite number of solutions
2) 3(x + 4) = 3x + 11
This has no solution because if you solve it, you're gonna get 12 = 11 and that is NEVER true. Whatever x is, 11 cannot equal 12!
